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3 years ago

Could someone please answer #35 for me

Mathematics

1 answer:

katrin2010 [14]3 years ago

4 0

Answer:

408

Step-by-step explanation:

Volume = length times width times height

So in this situation we can see that 17 is the length, 8 is the width, and 6 is the height

Knowing this information we can continue

If you think of a regular cube, you can split it diagonally and then it would be 2 triangles

So we can split the width, in halve which would be 4 and then apply the formula 4*6*17 and when you solve that you get 408 Now we have to split that in halve because remember it is a triangle and a triangle is halve of a square. Halve of 408 is 204.

If we repeat that prosses for the other side we will also get 204. Now we add 204+204 to get our answer 408.

Sorry is this was a little confusing but that's the best I can explain it.

Hope that helped and have a great day!

Step-by-step explanation:

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MatroZZZ [7]

Answer: 36 hotdogs

Step-by-step explanation: You need to find the least common multiple of 9 and 12.

You can check by multiplying 9 and 12 by consecutive whole numbers until you find a number that they match.

Example:

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3 years ago

Prove that the segments joining the midpoint of consecutive sides of an isosceles trapezoid form a rhombus.

sergiy2304 [10]

Answer:

See explanation

Step-by-step explanation:

a) To prove that DEFG is a rhombus, it is sufficient to prove that:

All the sides of the rhombus are congruent: $|DG|\cong |GF| \cong |EF| \cong |DE|$
The diagonals are perpendicular

Using the distance formula; $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$|DG|=\sqrt{(0-(-a-b))^2+(0-c)^2}$

$\implies |DG|=\sqrt{a^2+b^2+c^2+2ab}$

$|GF|=\sqrt{((a+b)-0)^2+(c-0)^2}$

$\implies |GF|=\sqrt{a^2+b^2+c^2+2ab}$

$|EF|=\sqrt{((a+b)-0)^2+(c-2c)^2}$

$\implies |EF|=\sqrt{a^2+b^2+c^2+2ab}$

$|DE|=\sqrt{(0-(-a-b))^2+(2c-c)^2}$

$\implies |DE|=\sqrt{a^2+b^2+c^2+2ab}$

Using the slope formula; $m=\frac{y_2-y_1}{x_2-x_1}$

The slope of EG is $m_{EG}=\frac{2c-0}{0-0}$

$\implies m_{EG}=\frac{2c}{0}$

The slope of EG is undefined hence it is a vertical line.

The slope of DF is $m_{DF}=\frac{c-c}{a+b-(-a-b)}$

$\implies m_{DF}=\frac{0}{2a+2b)}=0$

The slope of DF is zero, hence it is a horizontal line.

A horizontal line meets a vertical line at 90 degrees.

Conclusion:

Since $|DG|\cong |GF| \cong |EF| \cong |DE|$ and $DF \perp FG$ , DEFG is a rhombus

b) Using the slope formula:

The slope of DE is $m_{DE}=\frac{2c-c}{0-(-a-b)}$

$m_{DE}=\frac{c}{a+b)}$

The slope of FG is $m_{FG}=\frac{c-0}{a+b-0}$

$\implies m_{FG}=\frac{c}{a+b}$

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Step-by-step explanation:

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