Going side to side(horizontal) is always length and going up and down (vertical) width
Answer:
prime numbers only have two factors...
7 is the only prime in the list
Step-by-step explanation:
Answer:
y + 3 = (-1/2) x
Step-by-step explanation:
2x-y=-7
-y=-2x-7
y=2x+7
Slope m1= 2, perpendicular slope m2= -1/2
Equation of a line with perpendicular slope m2 and a point (0,-3) is
y - (-3) = (-1/2)(x - 0)
y + 3 = (-1/2) x
2y + 6 = - x
Answer:
b)(b²-a²)
Step-by-step explanation:
a cotθ + b cosecθ =p
b cotθ + a cosecθ =q
Now,
p²- q²
=(a cotθ + b cosecθ)² - (b cotθ + a cosecθ)² [a²-b²=(a+b)(a-b)]
=(acotθ+bcosecθ + bcotθ+ acosecθ) (a cotθ + bcosecθ -bcotθ-acosecθ)
={a(cotθ+cosecθ)+b(cotθ+cosecθ)} {a (cotθ-cosecθ)+b (cosecθ-cotθ)}
={a(cotθ+cosecθ)+b(cotθ+cosecθ)} [a (cotθ-cosecθ) + {- b (cotθ-cosecθ)} ]
={a(cotθ+cosecθ)+b(cotθ+cosecθ)} {a (cotθ-cosecθ) - b (cotθ-cosecθ)}
={(cotθ+cosecθ)(a+b)} {(cotθ-cosecθ) (a-b)}
=(cotθ+cosecθ) (a+b) (cotθ-cosecθ) (a-b)
=(cotθ+cosecθ) (cotθ-cosecθ) (a+b) (a-b)
= (cot²θ-cosec²θ) (a²-b²) [(a+b) (a-b)= (a²-b²)]
= -1 . (a²-b²) [ 1+cot²θ=cosec²θ ; ∴cot²θ-cosec²θ=-1]
=(b²-a²)
Answer:
m=3/2
Step-by-step explanation:
