Answer:
The maximum height of the projectile is 90 ft
Step-by-step explanation:
Here, we want to get the maximum height reached by the projectile
The answer here will be the y-coordinate value of the vertex form of the given equation
so firstly, we have to write the equation in the vertex form
We have this as;
y = -16t^2 + 64t + 26
That will be;
y = a(x-h)^2 + k
y = -16(x-2)^2 + 90
where the vertex of the equation is;
(-h,k)
K
in this case is 90 and thus, that is the maximum height of the projectile
Answer:
f(-2) = -1
Step-by-step explanation:
One way of doing this is to substitute -2 for x in every place where x shows up:
f(x) = 4x + 3x^2 − 5 → f(-2) = 4(-2) + 3(-2)^2 − 5
→ f(-2) = -8 + 3(4) - 5, or f(-2) = 4 - 5, or f(-2) = -1
Answer:
New height = 6
Step-by-step explanation:
The water is going to be the same volume no matter how the tank is orientated.
So you can do this 2 ways.
First way
Find the volume in the tank when the water goes up 24 cm on the height.
V = L*W*h
L = 8
W = 10
H = 24
V = 1920 cm^3
Now do it using the
L = 40
W = 8
h = ?
1920 = L * W * h
1920 = 40 * 8 * h
1920 = 320 * h
h * 320 = 1920
h = 1920/320
h = 6
Or you can do it without finding the 1920
L*W*h = L1 * w1 * h1
8*10*24 = 40 * 8 * h The 8's cancel
10*24 = 40*h Divide both sides by 10
24 = 4h Divide by 4
h = 6
Same as you got before.
Answer:
20%×60
1/5×60
i only help these two
Step-by-step explanation:
Answer:
6.9 I think.
Step-by-step explanation:
