The last two digits of the number can't be divisible by 4, so the entire number can't be divisible by four.
Answer:
if ∠Q=∠R
draw an angular bisector from P to QR in which it intersect wit Qr at point S
now we have two triangle : QPS and RSP
in which angle : QPS=RPS ( PS is angular bisector)
and we have angle Q and angle R are equal
and PS is common side
this makes triangle QPS and RSP are congruent by AAS(angle angle side)
which also means that pQ=PR ( proved)
Find area of circle
A=pir^2
A=pi5^2
A=25pi
then find how much the central angle is
whole circle is 2pi radians
(3pi/2)/2pi=3pi/4pi=3/4
it is 3/4 of whole area
area=25pi units^2
3/4 times 25pi=75/4pi units^2=
18 and 3/4 pi square units=
18.75ip square units
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