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ser-zykov [4K]
3 years ago
5

HELP ME THANKS +×+

Mathematics
2 answers:
Tresset [83]3 years ago
4 0

Answer:

hypotenuse =  \sqrt{ {height}^{2} +  {adjacent}^{2}  }  \\  =  \sqrt{ {11}^{2}  +  {60}^{2} }  \\  =  \sqrt{3721}  \\  = 61 \: inches

Elis [28]3 years ago
3 0

hypotenuse=

height

2

+adjacent

2

=

11

2

+60

2

=

3721

=61inches

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Orlando is measuring the angles of a triangle. He measures the first two angles and gets 30° and 70°. What should be the measure
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The answer will be B because all three angles of the triangles add up to180 degrees, and we already know the total of two other angles are 100 degrees, which made the unknown angles have 80 degrees. Hope it help!
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What is the operation symbol if the question is like this.<br> 52=8___(4___5)___20
stepan [7]

Answer:

52= 8×(4+5)-20

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3 years ago
What two rational expressions sum to 3x+4/x^2-6x+5?
Lubov Fominskaja [6]

Answer:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

Step-by-step explanation:

The given rational expression is:

\frac{3x+4}{x^{2}-6x+5} = \frac{3x+4}{(x-1)(x-5)}

We can use concept of Partial Fractions to solve this problem. Let,

\frac{3x+4}{(x-1)(x-5)}=\frac{A}{x-1} +\frac{B}{x-5}

Multiplying both sides by (x - 1)(x - 5), we get:

3x+4=A(x-5)+B(x-1)

Substituting x = 5, we get:

3(5)+4=A(5-5)+B(5-1)\\\\ 15+4=0+4B\\\\ 19=4B\\\\ B=\frac{19}{4}

Substituting x = 1, we get:

3(1)+4=A(1-5)+B(1-1)\\\\ 7=-4A\\\\ A=-\frac{7}{4}

Substituting the value of A and B, back in the original equation, we get:

\frac{3x+4}{x^2-6x+5}=\frac{-7}{4(x-1)} +\frac{19}{4(x-5)}

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2 years ago
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Answer:

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m∠ABE = m∠DBE

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m∠ABD = m∠ABE + m∠DBE

Because m∠ABE = 66°, therefore m∠DBE = 66°, so that

m∠ABD = 66° + 66° = 132°

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3 years ago
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cricket20 [7]

Answer:

4.70

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it is bigger then the other numbers

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