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3 years ago

Find the area of the isosceles triangle. please help thanks

Mathematics

1 answer:

fiasKO [112]3 years ago

5 0

Answer:

1080 m^2 Don't submit m^2 in your answer.

Step-by-step explanation:

Givens

The catch is to find h

To do that, use a^2 + b^2 = c^2

a b and c are in the same 1/2 triangle.

a = 48/2 = 24 m

b = h = ?

c = 51 meters

Solution

a^2 + b^2 = 51^2 Substitute for b^2 = h^2

24^2 + h^2 = 51^2 Expand 24^2 and 51^2

576 + h^2 = 2601 Subtract 576 from both sides

h^2 = 2601 - 576

h^2 = 2025 Take the square root of both sides

h = 45

Area

Area = 1/2 b * h

Area = 1/2 48 * 45

Area = 1080

Remark

Notice that to find h you only use 1/2 of 48 because that is the base of the right triangle.

To find the area, you need to use all of 48 because 48 is the full length of the base.

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2 years ago

Someone help I don't know what the diameter or radius is

Elenna [48]

<h3>Answer:</h3>

52.38 inch² & 261.90 inch²

<h3>Step-by-step explanation:</h3>

Here we need to find the area of the sector . So according to formula we know the area of sector as ,

$\boxed {\sf Area_{(sector)}= \dfrac{\theta}{360}\times \pi r^2 }$

Here we can see that the central angle subtended by the arc is 60° and the radius of the circle is 10 inches . So the required area would be ,

=> Area = ∅/ 360° × π r²

=> Area = 60°/360° × 22/7 × (10in.)²

=> Area = 1/6 * 22/7 * 100 in²

=> Area = 52 .380 in²

<h3>★ Hence the area of the red sector is 52.38 inch².</h3>

_________________________________

Now let's find out the area of blue sector .The angle subtended by the arc will be (360-60)°=300° .

=> Area = 300/360 × 22/7 × 100 in²

=> Area = 261. 90 in²

<h3>★ Hence the area of blue sector is 261.90 inch².</h3>

$\boxed{\red{\sf Area _{(red \ sector )} = 52.38 in^2 }}$

$\boxed{\blue{\sf Area _{(blue \ sector )} = 261.90 in^2 }}$

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3 years ago