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Vinil7 [7]
3 years ago
13

Please help me with #14 and #15

Mathematics
1 answer:
RSB [31]3 years ago
6 0
What is 14 and 15 tell me 
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Can anyone help me with my math homework! My teacher didn't even discuss it! I would appreciate it! Thank you!
Hatshy [7]
Please, in the future, post just one problem at a time.

Looking at Problem #1:  The line intersects the y-axis at (0,-3) and intersects the x-axis at (1,-1).  At least, this is what I see; your graph is small.
                                                                           -3-[-1]
The slope of that line is then  m = rise / run = ------------ = +2.
                                                                            0 - 1
                                       [change in y]
Slope = m = rise / run = --------------------
                                        [change in x]
8 0
3 years ago
Directions: Follow the instructions for the following inequalities. 1. 4<7 Multiply both sides by 7 , then by 6, then by 3, t
worty [1.4K]

In the given question, we have to perform this experiment and test if the inequality is true or not.

Adding the same value to both sides of the inequality will not change the inequality sign

<h3>Inequality</h3>

data;

  • 4 < 7
  • 11 > - 2
  • -4 < - 2
  • -8 < 8

In the first case, we would do follow the process

6 * 7 * 4 < 7 * 7 * 6\\168 < 294

In the second case;

11 > - 2\\\\5 + 11 > -2 + 5\\3 + 16 > 3 + 3\\4+ 19 > 6 + 4\\23 > 10

In all the scenarios, the operations did not affect the inequality sign because we are doing it equally to all side and at the end of the day nullifies each other.

Learn more on inequality here;

brainly.com/question/24372553

#SPJ1

4 0
2 years ago
What is the length of the altitude of the equilateral triangle below
ale4655 [162]
Using Sine.

Sine = Opposite / Hypotenuse

sin 60° = a / (6√3)                        But sin60° = √3/2

√3/2 = a/(6√3)

Cross multiply

2*a = 6√3 * √3

2a = 6 * √(3*3)

2a = 6*3

a = 6*3/2

a = 3*3 = 9

Option E.

Hope this helps.
4 0
3 years ago
A school bought pens, each costing $1, and pencils, each costing $0.5. The cost of the whole purchase was $220. How many pens an
Aleks [24]

Answer:

<u>The number of pens = 120 and the number of pencils = 200</u>

Step-by-step explanation:

Let the number of pens x, and the number of pencils is y

the cost of one pen $1, and the cost of one pencil $0.5

The cost of the whole purchase was $220

1 * x + 0.5 * y = 220

x + 0.5 y = 220 ⇒ eq.(1)

there were 80 more pencils than pens

y - x = 80 ⇒ eq.(2)

from eq.(2) x = y - 80

By substitution with x from the last equation at eq.(1)

∴ (y - 80) + 0.5 y = 220

1.5y = 220 + 80 = 300

y = 300/1.5 = 200

x = y - 80 = 200 - 80 = 120

<u>So, the number of pens = 120 and the number of pencils = 200</u>

7 0
3 years ago
3. For the equation-4y = &amp;r, what is the constant of variation? (1 point)<br> ООО<br> 02
alexandr1967 [171]

Answer:

3).

- 4y = 8x \\  \frac{y}{x}  =  \frac{8}{ - 4}  \\  \frac{y}{x} =  - 2 \\ y =  - 2x \\ hence \: constant \: is \:  - 2

4).

y \alpha x \\ y = kx \\ where \: k \: is \: the \: constant \: of \: proportionality \\ when \: y = 24 \: and \: x = 8 \\ substitute \: in \: y = kx \\ 24 = 8k \\ k =  \frac{24}{8}  \\ k = 3 \\ value \: of \: constant = 3

If it was by 10, k = 3 by 10

k = 30

5).

general \: equation \: of \: line  \\ y = mx + c \\ but \: m =  \frac{2}{3}  \: and \: c = 9 \\ substitute \: for \: m \: and \: c \: in \: y = mx + c \\ y =  \frac{2}{3} x + 9 \\ alternatively \\ 3y = 2x + 27

7 0
3 years ago
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