Select the equation that represents the problem let x represent the unknow number

Find the perimeter of a rectangle with a length of 6x+3 and a width of -2x-5.

blsea [12.9K]

The simple way of calculating a perimeter is to add all of the sides.
For a rectangle this would equal 2 x length + 2 x width
P = 2(6x + 3) + 2(-2x - 5)
= 12x + 6 - 4x - 10
= 8x - 4

At a higher level both the length and width must be greater than zero (= zero is a trivial rectangle)
6x + 3 > 0
6x > -3
x > -0.5

-2x - 5 > 0
2x + 5 < 0 (multiplying by -1 reverses the inequality)
2x < -5
x < -2.5

This rectangle cannot exist as x cannot be < -2.5 and > -0.5 at the same time!

8 0

3 years ago

Read 2 more answers

If the restaurant bill is $21.60, and I want to leave a 15% tip for my waitress, how much money should I leave for the tip?

Nadusha1986 [10]

Answer:

$3.24

Step-by-step explanation:

3 0

4 years ago

the breadth of a rectangular painting is 65 cm. its length is 137 cm more than its breadth. what is the area of the painting?

Marysya12 [62]

Answer:

8,905cm²

Step-by-step explanation:

Area= Length × Breadth

=137cm × 65cm

= 8,905cm²

7 0

3 years ago

Name the angle in 2 different ways and name the 2 rays from the diagram below please show work

timama [110]

Answer:

3) TB and NT

4) ∠KLM and ∠MLK

Step-by-step explanation:

3) those two rays intersect to form the angle shown in the diagram

4) an angle can always be named from left to right or right to left as long as the middle letter is always the vertex of the angle

3 0

3 years ago

Read 2 more answers

Given the data shown below, which of the following is the best prediction for

Soloha48 [4]

Answer:

The best prediction for the number of years it will take for the population to reach 200,000 is 9.41

Step-by-step explanation:

Year Population

1 11,920

2 16,800

3 23,300

4 33,000

5 45,750

6 64,000

$y_1 =A _0 e ^{kt _1}\\y_2 = A_0 e^{k t_2}\\(t_1,y_1)=(1,11920)\\(t_2,y_2)=(2,16800)$

Substitute the values

$11920=A _0 e ^{k} ---1\\16800 = A_0 e^{2k} ---2$

Divide 1 and 2

$\frac{11920}{16800}=\frac{e^k}{e^{2k}}\\\frac{11920}{16800}=e^{k-2k}\\ln(\frac{11920}{16800})=-k\\k=-1 ln(\frac{11920}{16800})\\k=0.3432\\A_0=y_1 e^{-k t_1}\\A_0=11920 e^{-0.3432}\\A_0=8457.5238$

The exponential function that passes through the points (1, 11920) and (2, 16800) is $y=8457.5238 e^{0.3432t}$

Now we are supposed to find the best prediction for the number of years it will take for the population to reach 200,000

$200000=8457.5238 e^{0.3432t}$

$\frac{200000}{8457.5238}=e^{0.3432t}$

$ln(\frac{200000}{8457.5238})=0.3432t$

t = 9.41

Hence the best prediction for the number of years it will take for the population to reach 200,000 is 9.41

6 0

4 years ago