2 years ago

Simply the following

Mathematics

1 answer:

Pachacha [2.7K]2 years ago

6 0

Answer:

Step-by-step explanation:

$\Bigg[\bigg[ [1/n]^{-1}\bigg]^{-1} \Bigg] ^{-1}$

= $\bigg[ [1/n]^{-1}\bigg]^{(-1) (-1)}$

= $\bigg[ [1/n]^{-1}\bigg]^{1}$

= $[1/n]^{-1\times 1}$

= $[1/n]^{-1}$

= $[1/n^{-1}]$

= n

Hope it helps you in your learning process

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