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tester [92]
3 years ago
14

Simply the following​

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
6 0

Answer:

n

Step-by-step explanation:

\Bigg[\bigg[ [1/n]^{-1}\bigg]^{-1} \Bigg] ^{-1}

=\bigg[ [1/n]^{-1}\bigg]^{(-1) (-1)}

=\bigg[ [1/n]^{-1}\bigg]^{1}

=[1/n]^{-1\times 1}

=[1/n]^{-1}

=[1/n^{-1}]

= n

Hope it helps you in your learning process

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