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3 years ago

Y = 3.2 Solve the following system of equations by substitution. 3x -9x + 3y = 1

Mathematics

2 answers:

Anettt [7]3 years ago

7 0

$\huge\text{Hey there!}$

$\huge\text{3x - 9x + 3y = 1}\\\huge\text{\boxed{\rightarrow} -6x + 3y = 1}\\\huge\text{\boxed{\rightarrow} -6x + 3(3.2) = 1}\\\huge\text{\boxed{\rightarrow} -6x + 9.6 = 1}$

$\huge\textsf{SUBTRACT \underline{\underline{9.6}} to BOTH SIDES}\\\huge\text{-6x + 9.6 - 9.6 = 1 - 96}\\\\\\\huge\textsf{DIVIDE \underline{\underline{-6}} to BOTH SIDES}\\\\\huge\boxed{\dfrac{-6\mathsf{x}}{-6}= \dfrac{-8.6}{-6}}$

$\huge\textsf{SIMPLIFY ABOVE \& YOU HAVE YOUR}\\\huge\textsf{RESULT OF THE X-VALUE}\\\\\\\boxed{\huge\boxed{\huge\textsf{x = \bf 1.433333 or } \mathsf{x = \bf \dfrac{8.6}{6}}}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}\\\\\\\\\boxed{\huge\boxed{\frak{Amphitrite1040:)}}}$

steposvetlana [31]3 years ago

3 0

3x-9x+3(3.2)=1

3x-9x+9.6=1
-9.6. -9.6
-6x=-8.6
X=-8.6/-6=1.433333333

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The number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.

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Probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is 0.89435.

Step-by-step explanation:

We are given that the number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.

Also, sample of 49 adults is given.

Let X = number of hours spent per week on household chores

So, assuming data follows normal distribution; X ~ N( $\mu=28,\sigma^{2}=7^{2}$ )

The z score probability distribution for sample mean is given by;

Z = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = mean hours = 28

$\sigma$ = standard deviation = 7 hours

n = sample of adults = 49

Let $\bar X$ = sample mean hours spent per week on household chores

So, probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is given by =P( $\bar X$ > 26.75 hours)

P( $\bar X$ > 26.75 hours) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{26.75-28}{\frac{7}{\sqrt{49} } }$ ) = P(Z > -1.25) = P(Z < 1.25)