Question

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Answer 1

Answer:

$T_1 = 8$

$T_2 = 14$

$T_3 = 22$

Step-by-step explanation:

Given

$T_n = n^2 + 3n + 4$

Required:

Find the first 3 terms

To do this, we take the values of n to be 1,2 and 3.

For the first term; n = 1

$T_n = n^2 + 3n + 4$

$T_1 = 1^2 + 3*1 + 4$

$T_1 = 1+ 3+ 4$

$T_1 = 8$

For the second term; n = 2

$T_n = n^2 + 3n + 4$

$T_2 = 2^2 + 3 * 2 + 4$

$T_2 = 4 + 6+ 4$

$T_2 = 14$

For the third term; n = 3

$T_n = n^2 + 3n + 4$

$T_3 = 3^2 + 3 * 3 + 4$

$T_3 = 9 + 9 + 4$

$T_3 = 22$