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Oksanka [162]
3 years ago
10

Brainliest for correct answers

Mathematics
1 answer:
larisa [96]3 years ago
6 0

Answer:

there positive

Step-by-step explanation:

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Find a compound proposition involving the propositional variables p, q, and r that is true when exactly two of p, q, and r are t
VLD [36.1K]

Answer:

Consider the proposition C=(p∧q∧¬r)∨(p∧¬q∧r)∨(¬p∧q∧r)

Step-by-step explanation:

This compound proposition C uses the outer disjunction (∨) then the proposition is true if and only if one of the three propositions (p∧q∧¬r),(p∧¬q∧r),(¬p∧q∧r) is true.

First, it is impossible that two or three of these propositions are simultaneously true. For example, if (p∧q∧¬r) and (p∧¬q∧r) are both true, then ¬r is true (from the first conjuntion) and r is true (from the second one), a contradiction. All the other possibilities can be discarded reasoning in the same way.

Since these propositions are mutually excluyent, C is true if and only if exactly one of the three propositions is true (and false otherwise). This can only happen if exactly two of p,q, and r are true and the other one is false. For example, (p∧q∧¬r) is true when p and q are true, and r is false.

8 0
4 years ago
A circle has a radius of 40 centimeters. Find the length of the arc intercepted by a central angle of 5π/3. Express the answer i
VARVARA [1.3K]
Well if you have a radius remember to divide by 2 . So divide your number by 2. And you should get 5x
6 0
3 years ago
Which of the following is the inverse to the function f(x)=-8-5x
-Dominant- [34]
Step 1: Replace f(x) with y: y=-8-5x
Step 2: Switch X and Y: X=-8-5y
Step 3:Solve for y: x+8=-5y ≈ y=(x+8)/-5
Step 4: Replace y with F^-1(x): f^-1(x)=(x+8)/-5 :)
6 0
3 years ago
Find the number which replaces the question mark​
Sati [7]

I think it would be 40?

8 0
2 years ago
Which of these is the area of a sector of a circle with r = 18”, given that its arc length is 6π?
koban [17]
The formulas for arc length and area of a sector are quite close in their appearance.  The formula for arc length, however, is related to the circumference of a circle while the area of a sector is related to, well, the area! The arc length formula is AL= \frac{ \beta }{360} *2 \pi r.  Notice the "2*pi*r" which is the circumference formula.  The area of a sector is A s= \frac{ \beta }{360}  * \pi r ^{2}.  Notice the "pi*r squared", which of course is the area of a circle.  In our problem we are given the arc length and the radius.  What we do not have that we need to then find the area of a sector of the circle is the measure of the central angle, beta.  Filling in accordingly, 6 \pi = \frac{ \beta }{360} *2 \pi (18).  Simplifying by multiplying by 360 on both sides and then dividing by 36 on both sides gives us that our angle has a measure of 60°.  Now we can use that to find the area of a sector of that same circle.  Again, filling accordingly, A_{s} = \frac{60}{360} * \pi (18) ^{2}, and A_{s} =54 \pi.  When you multiply in the value of pi, you get that your area is 169.65 in squared.
8 0
3 years ago
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