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adelina 88 [10]
3 years ago
5

Find a compound proposition involving the propositional variables p, q, and r that is true when exactly two of p, q, and r are t

rue and is false otherwise.
Mathematics
1 answer:
VLD [36.1K]3 years ago
8 0

Answer:

Consider the proposition C=(p∧q∧¬r)∨(p∧¬q∧r)∨(¬p∧q∧r)

Step-by-step explanation:

This compound proposition C uses the outer disjunction (∨) then the proposition is true if and only if one of the three propositions (p∧q∧¬r),(p∧¬q∧r),(¬p∧q∧r) is true.

First, it is impossible that two or three of these propositions are simultaneously true. For example, if (p∧q∧¬r) and (p∧¬q∧r) are both true, then ¬r is true (from the first conjuntion) and r is true (from the second one), a contradiction. All the other possibilities can be discarded reasoning in the same way.

Since these propositions are mutually excluyent, C is true if and only if exactly one of the three propositions is true (and false otherwise). This can only happen if exactly two of p,q, and r are true and the other one is false. For example, (p∧q∧¬r) is true when p and q are true, and r is false.

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Seeds are often treated with fungicides to protect them in poor-draining, wet environments. A small-scale trial, involving six t
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Answer:

0.0076 = 0.76% probability that all five plants emerged from treated seeds

Step-by-step explanation:

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Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

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C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

6 + 6 = 12 seeds, which means that N = 12

6 treated, which means that k = 6

Five sprouted, which means that n = 5

What is the probability that all five plants emerged from treated seeds?

This is P(X = 5). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 5) = h(5,12,5,6) = \frac{C_{6,5}*C_{6,0}}{C_{12,5}} = 0.0076

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3 0
3 years ago
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Answer:

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Step-by-step explanation:

Let monthly living expense be "x"

and monthly fixed expense be "y"

<u>"monthly living expenses were 400 more than his monthly fixed expenses":</u>

x = 400 + y

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x + y = 4350

Putting Equation 1 in Equation 2:

(400 + y) + y = 4350

400 + 2y = 4350

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y = 1975

Now, x = 400 + y = 400 + 1975 = 2375

8 0
3 years ago
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