Question

If f(x)=3x^2-2x+4 and g(x)=5x^2+6x-8,find (f-g) (x)

Answer 1

Answer:

$- 2( {x}^{2} - 4x + 6)$

Step-by-step explanation:

$f(x)=3x^2-2x+4 \\ g(x)=5x^2+6x-8 \\ (f-g) (x) = 3 {x}^{2} - 2x + 4 - (5 {x}^{2} + 6x - 8) \\ = 3 {x}^{2} - 2x + 4 - 5 {x}^{2} - 6x + 8 \\ = - 2 {x}^{2} - 8x + 12 \\ = - 2( {x}^{2} - 4x + 6)$

Answer 2

Answer:

-2x^2-8x+12

Step-by-step explanation:

f(x)=3x^2-2x+4

g(x)=5x^2+6x-8

(f-g) (x)= 3x^2-2x+4 - (5x^2+6x-8)

Distribute the minus sign

(f-g) (x)= 3x^2-2x+4 - 5x^2-6x+8

Combine like terms

          =-2x^2-8x+12