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3 years ago

The top of a table has a length of 7 feet and a width of 5 feet. what is the area of the table top

Mathematics

1 answer:

gladu [14]3 years ago

7 0

Answer: 35ft

Step-by-step explanation:

The area for a rectangle or square is Width times Length (W*L)

So we can take our given measurements and multiply them

$5*7=35$

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3 years ago

Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function.

seropon [69]

Answer:

$h'(x)=\frac{3r^{2}}{2\sqrt{r^3+5}}$

Step-by-step explanation:

1) The Fundamental Theorem of Calculus in its first part, shows us a reciprocal relationship between Derivatives and Integration

$g(x)=\int_{a}^{x}f(t)dt \:\:a\leqslant x\leqslant b$

2) In this case, we'll need to find the derivative applying the chain rule. As it follows:

$h(x)=\int_{a}^{x^{2}}\sqrt{5+r^{3}}\therefore h'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left (\int_{a}^{x^{2}}\sqrt{5+r^{3}}\right )\\h'(x)=\sqrt{5+r^{3}}\\Chain\:Rule:\\F'(x)=f'(g(x))*g'(x)\\h'=\sqrt{5+r^{3}}\Rightarrow h'(x)=\frac{1}{2}*(r^{3}+5)^{-\frac{1}{2}}*(3r^{2}+0)\Rightarrow h'(x)=\frac{3r^{2}}{2\sqrt{r^3+5}}$

3) To test it, just integrate:

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3 years ago

The height of a flagpole is one-quarter of the height of a bridge.

DedPeter [7]

Answer:

the height of the flagpole is three fourths the height of the school. the difference in there heights is 4.5 m. what is the height of the school?

----------

Equation:

f = (3/4)s

s-f = 4.5

----

Substitute for "f" and solve for "s":

s-(3/4)s = 4.5

(1/4)s = 4.5

s = 4*4.5

s = 18 meters (height of the school)

---------------

Since f = (3/4)s, f = (3/4)(18)

= (3/2)(9)= 13.5 meters (height of the flag pole)

===============================-step explanation: HOPE THIS HELPS

6 0

3 years ago

Read 2 more answers