Answer:
Step-by-step explanation:
we know that
The area of the shaded sections is equal to the area of the circle minus the area of the triangle
so
where
----> the radius is half the diameter
substitute
<h2><em>Given PR + QR = 25 , PQ = 5
</em></h2><h2><em>PR be x. and QR = 25 - x </em></h2><h2><em>
</em></h2><h2><em>Pythagoras theorem ,PR2 = PQ2 + QR2
</em></h2><h2><em>
</em></h2><h2><em>x2 = (5)2 + (25 - x)2
</em></h2><h2><em>
</em></h2><h2><em>x2 = 25 + 625 + x2 - 50x
</em></h2><h2><em>50x = 650
</em></h2><h2><em>x = 13
</em></h2><h2><em> </em></h2><h2><em>
</em></h2><h2><em> PR = 13 cm
</em></h2><h2><em>QR = (25 - 13) cm = 12 cm
</em></h2><h2><em>
</em></h2><h2><em>sin P = QR/PR = 12/13
</em></h2><h2><em>
</em></h2><h2><em>cos P = PQ/PR = 5/13
</em></h2><h2><em>
</em></h2><h2><em>tan P = QR/PQ = 12/5 </em></h2><h2><em /></h2><h2><em>HOPE IT HELPS (◕‿◕✿)</em></h2>
Answer:
Step-by-step explanation:
The ratio of boys to girls is
7
:
11
, and there are
49
boys, so therefore there are
49
7
⋅
11
=
77
girls
Total number of boys and girls in the classroom is
77
+
49
=
126
.
Although I am not clear as to whether the radius is r—1 or otherwise, but if i work with the values i see then:
Volume — T. S. A.
= πr²h — (2πr²+2πrh)
So after the simplification, I substitute the values given,
r= r—1 and h=h—1
And the answer is...
π(r—1)(rh—3r—3h+5)!
