10. In APQR, right-angled at Q, PR+QR = 25 cm and PQ = 5 cm. Determine the values of

1 answer:

6 0

<h2><em>Given PR + QR = 25 , PQ = 5 </em></h2><h2><em>PR be x. and QR = 25 - x </em></h2><h2><em> </em></h2><h2><em>Pythagoras theorem ,PR2 = PQ2 + QR2 </em></h2><h2><em> </em></h2><h2><em>x2 = (5)2 + (25 - x)2 </em></h2><h2><em> </em></h2><h2><em>x2 = 25 + 625 + x2 - 50x </em></h2><h2><em>50x = 650 </em></h2><h2><em>x = 13 </em></h2><h2><em> </em></h2><h2><em> </em></h2><h2><em> PR = 13 cm </em></h2><h2><em>QR = (25 - 13) cm = 12 cm </em></h2><h2><em> </em></h2><h2><em>sin P = QR/PR = 12/13 </em></h2><h2><em> </em></h2><h2><em>cos P = PQ/PR = 5/13 </em></h2><h2><em> </em></h2><h2><em>tan P = QR/PQ = 12/5 </em></h2><h2><em /></h2><h2><em>HOPE IT HELPS (◕‿◕✿)</em></h2>

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