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2 years ago

Solve for x. Help Help Help Help Help, I tried dividing 17/2 which gave me 8.5 but it’s wrong

Mathematics

1 answer:

3241004551 [841]2 years ago

5 0

Answer:

x = 15.9

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

6^2 + x^2 = 17^2

36+ x^2 = 289

x^2 = 289-36

x^2 =253

Take the square root of each side

sqrt(x^2) = sqrt( 253)

x = 15.90597

Rounding to the nearest tenth

x = 15.9

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The sum of two polynomials is 8d^5-3c^3d^2+5c^2d^3-4CD^4+9. If one added is 2d^5-c^3d^4+8CD^4+1, what is the other added

insens350 [35]

Answer:

6d^5 - 3c^3d^2 + 5c^2d^3 + c^3d^4 - 12cd^4 + 8

Step-by-step explanation:

We need to subtract the given polynomial from the sum:-

8d^5 - 3c^3d^2 + 5c^2d^3 - 4cd^4 + 9 - (2d^5 - c^3d^4 + 8cd^4 +1 )

We need to distribute the negative over the parentheses:-

= 8d^5 - 3c^3d^2 + 5c^2d^3 - 4cd^4 + 9 - 2d^5 + c^3d^4 - 8cd^4 -1

Bringing like terms together:

= 8d^5 - 2d^5 - 3c^3d^2 + 5c^2d^3 + c^3d^4 - 4cd^4 - 8cd^4 + 9

- 1

Simplifying like terms

= 6d^5 - 3c^3d^2 + 5c^2d^3 + c^3d^4 - 12cd^4 + 8

8 0

3 years ago

What is the value of sin-1(1)? negative startfraction pi over 2 endfraction 0 startfraction pi over 2 endfraction π

mariarad [96]

The value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.

<h3>What is the value of sin (π/2)?</h3>

The value of sin (π/2) is equal to the number 1. The value of the sin-1(1) has to be find out.

Suppose the value of this function is <em>x</em>. Thus,

$x=\sin^{-1}(1)$

Solve it further,

$\sin(x)=(1)$ ......1

The value of sin (π/2) and -sin (-π/2) is equal to 1 such that,

$\sin\dfrac{\pi}{2}=-\sin\left(-\dfrac{\pi}{2}\right)=1$

Put this value in the equation 1,

$\sin(x)=\sin\left(\dfrac{\pi}{2}\right)=-\sin\left(-\dfrac{\pi}{2}\right)$

Thus, the range will be,

$\left(\dfrac{\pi}{2},-\dfrac{\pi}{2}\right)$

Thus, the value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.

Learn more about the sine values here;

brainly.com/question/10711389

3 0

3 years ago

Please help :(<br>Solve the qaudratic equation given below<br>(9x + 13)² = 49(9x + 13)² = 49

NemiM [27]

Answer:

Im pretty sure ur answers would be

x= -32/27 and X= -46/27

Step-by-step explanation:

So srry if im wrong tho

5 0

3 years ago

A college conducts a common test for all the students. For the Mathematics portion of this test, the scores are normally distrib

Jet001 [13]

Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 502, \sigma = 115$

The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:

X = 590:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{590 - 502}{115}$

Z = 0.76

Z = 0.76 has a p-value of 0.7764.

X = 400:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{400 - 502}{115}$

Z = -0.89

Z = -0.89 has a p-value of 0.1867.

0.7764 - 0.1867 = 0.5897 = 58.97%.

58.97% of students would be expected to score between 400 and 590.

More can be learned about the normal distribution at brainly.com/question/27643290

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2 years ago

Use the drop-down menus to identify the career that matches each description.

jolli1 [7]

Answer:

D, B, C, and B

Step-by-step explanation:

I just did it

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3 years ago