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Papessa [141]
2 years ago
11

A hydrogen atom is about 5×10 to the -11 power

Mathematics
1 answer:
Olegator [25]2 years ago
8 0

Factors are numbers that can be multiplied by an integer to obtain the desired integer

The size of the human hair is <u>1.0 × 10⁻⁴ meters </u>

Reason:

The given parameters are;

The size of an hydrogen atom is 5 × 10⁻¹¹   meters

The width of the human hair is 6 times as big

Therefore, we have;

The width of the human hair is 2 × 10⁶ times as big, therefore, we have;

The size of the human hair = 5× 10⁻¹¹ × 2 × 10⁶ = 1.0 × 10⁻⁴

The size of the human hair is <u>1.0 × 10⁻⁴ meters</u>

Learn more about factors here:

brainly.com/question/17176261

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Good Morning everyone! I need help please! :) First gets Brainliest
kicyunya [14]

Answer:

C. The distribution for town A is positively skewed, but the distribution for town B is symmetric.

Hope it helps you out!

5 0
3 years ago
find the area of field in a form of trapezium whose parallel sides are 10 and 12 and perpendicular distance between them is 6 me
IRISSAK [1]

Answer:

66 m²

Step-by-step explanation:

A = ½ (a + b) h

A = ½ (10 + 12) (6)

A = 66

The area is 66 m².

7 0
4 years ago
Adele and her best friend, Valentina, want to rent a canoe to explore the lake by their campsite. The Boat Bunker charges $27 fo
LiRa [457]

Answer:

Oar City

Step-by-step explanation:

Divide the first expense (27) by the time you ride (3 hours) and you get 9 dollars an hour

Divide the second expense (45) by the time you ride (9 hours) and you get 5 dollars an hour

6 0
3 years ago
What is the probability of rolling a number greater than or equal to 9 with the sum of two dice, given that at least one of the
olga55 [171]
Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
6 0
3 years ago
Which of the following is true for the number of trials for a binomial experiment. Explain your answer. The number of trials in
viktelen [127]

Answer:

The correct option is C.

Step-by-step explanation:

Consider the provided information.

Four conditions of a binomial experiment:

There should be fixed number of trials

Each trial is independent with respect to the others

The maximum possible outcomes are two

The probability of each outcome remains constant.

Now, observe the provided options:

Option A and B are not possible as they doesn't satisfy the conditions of binomial experiment which is there must be fixed number of trials.

Now observe the option C which state that there must be fixed number of trials, it satisfy the condition of a binomial experiment.

Therefore, the correct option is C.

7 0
3 years ago
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