Answer:

Step-by-step explanation:
The domain of a rational function is all real numbers <em>except </em>for when the denominator equals 0.
So, to find the domain restrictions, set the denominator to 0 and solve for x.
We have the rational function:

Set the denominator to 0:

Subtract 9:

So, the domain is all real numbers except for -9.
In other words, our domain is all values to the left of negative 9 and to the right of negative 9.
In interval notation, this is:

And we're done :)
Answer:
the answer will be Root 2
Step-by-step explanation:
x^2 = 1^2 + 1^2
We take the unmentioned side as 1 because it is an isosceles triangle and thus 2 of the sides will have the same measure
x^2 = 1 + 1
x^2 = 2
taking square root on both the sides
x = root of 2
Answer:

Step-by-step explanation:
The function that we have to study in this problem is

The domain of a function is defined as the set of all the possible values of x that the function can take.
For a square-root function, there are some limitations to the possible value of the argument in the root.
In particular, the argument of a square root must be equal or greater than zero, because the square root of a negative number is not defined.
Therefore, in this case, we have to set the following condition for the domain:

And by solving, we get

which means that the domain of this function is all real numbers equal or greater than 5.
Answer:
1.2
Step-by-step explanation:
1
=1.2
Answer:
-2x+4
Step-by-step explanation:
-2(x-3)-2
-2x+6-2
-2x+4