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PtichkaEL [24]
3 years ago
8

The question has a period I don’t know why

Mathematics
1 answer:
Xelga [282]3 years ago
7 0
It is not a question it’s telling you to do it haha! But just divide the (hours of / days) for example 7/2 and that would be your answer!
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In the diagram, point O is the center of the circle and mADB = 43°. If mAOB = mBOC, what is mBDC?
Vanyuwa [196]
The answer is B) 43<span>°
Angle ADB is an inscribed angle which means arc AB has an angle twice that of angle ADB. The angle of the arc would be the same as that of the central angle AOB. So, mAOB = 86</span>°. And since, mAOB = mBOC, then mBOC = 86° and arc BC has a measure of 86° as well. Angle BDC intercepts the arc BC which means half of the angle of arc BC is mBDC. So, mBDC = 43<span>°.</span>
7 0
3 years ago
Read 2 more answers
HURYYYYYYYYYYYYYYYYYYYYYY
Crazy boy [7]

Answer:

The answer is C.

Step-by-step explanation:

Hope this helps!

5 0
2 years ago
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A hat that originally cost 12.50 with a 60% markup find the total cost
cluponka [151]

Answer:

$20.00 dollars will be the new cost.

Step-by-step explanation:

Multiply $12.50 and 60% to get $7.50.

$7.50 plus $12.50 is $20.00.

5 0
2 years ago
PLEASE HELP ASAP -- WITH THE WORKK<br><br>50 points
MAXImum [283]

Part-A:-

<h3>(f×g)=</h3>

\\ \sf\longmapsto x^2+3x-70(4x-12)

\\ \sf\longmapsto 4x^2+12x-280-12x^2+36x+840

\\ \sf\longmapsto -8x^2+48x+560

Now

\\ \sf\longmapsto (f.g)(3)

\\ \sf\longmapsto -8(3)^2+48(3)+560

\\ \sf\longmapsto -72+144+560

\\ \sf\longmapsto 72+560

\\ \sf\longmapsto 632

Part-B:-

\\ \sf\longmapsto f(3)

\\ \sf\longmapsto (3)^2+3(3)-70

\\ \sf\longmapsto 9+9-70

\\ \sf\longmapsto 18-70

\\ \sf\longmapsto -52

Now

\\ \sf\longmapsto g(f(3))

\\ \sf\longmapsto g(-52)

\\ \sf\longmapsto 4(-52-3)

\\ \sf\longmapsto 4(-55)

\\ \sf\longmapsto -220

Part:-C

\\ \sf\longmapsto g(-2)

\\ \sf\longmapsto 4(-2-3)

\\ \sf\longmapsto 4(-5)

\\ \sf\longmapsto -20

Now

\\ \sf\longmapsto f(g(-2))

\\ \sf\longmapsto f(-20)

\\ \sf\longmapsto (-20)^2+3(-20)-70

\\ \sf\longmapsto 400-60-70

\\ \sf\longmapsto 400-130

\\ \sf\longmapsto 270

Part-D:-

  • g×f=f×g

\\ \sf\longmapsto (g.f)(-2)

\\ \sf\longmapsto -8(-2)^2+48(-2)+560

\\ \sf\longmapsto 32-96+560

\\ \sf\longmapsto -64+560

\\ \sf\longmapsto 496

6 0
2 years ago
Need help solving this problem
ANTONII [103]
Here is the solution for the eqns.

6 0
3 years ago
Read 2 more answers
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