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3 years ago

In the diagram, point O is the center of the circle and mADB = 43°. If mAOB = mBOC, what is mBDC?

Mathematics

2 answers:

Vanyuwa [196]3 years ago

7 0

The answer is B) 43°
Angle ADB is an inscribed angle which means arc AB has an angle twice that of angle ADB. The angle of the arc would be the same as that of the central angle AOB. So, mAOB = 86°. And since, mAOB = mBOC, then mBOC = 86° and arc BC has a measure of 86° as well. Angle BDC intercepts the arc BC which means half of the angle of arc BC is mBDC. So, mBDC = 43°.

kirill115 [55]3 years ago

6 0

It is B 43. This is correct for sure.

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To determine whether each expression is equivalent to $2x + 4y - 5 + 3x + 8 - 4y$ , apply the knowledge of algebra to solve each of the following in it's simplest form.

First, simplify $2x + 4y - 5 + 3x + 8 - 4y$ as follows:

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First Option

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$2x + 4y - 5 + 3x + 8 - 4y\\2x + 3x + 4y - 4y -5+8\\5x + 3$

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Check the box for YES.

Second Option:

$6xy + 3 - 4y$ (cannot be simplified further)

$6xy + 3 - 4y\neq 2x + 4y - 5 + 3x + 8 - 4y$

Therefore:

Leave the box BLANK for NO.

Third Option:

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Therefore:

Leave the box BLANK for NO.

Fourth Option:

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$5x + 3 = 2x + 4y - 5 + 3x + 8 - 4y$

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