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Firlakuza [10]
3 years ago
8

In the diagram, point O is the center of the circle and mADB = 43°. If mAOB = mBOC, what is mBDC?

Mathematics
2 answers:
Vanyuwa [196]3 years ago
7 0
The answer is B) 43<span>°
Angle ADB is an inscribed angle which means arc AB has an angle twice that of angle ADB. The angle of the arc would be the same as that of the central angle AOB. So, mAOB = 86</span>°. And since, mAOB = mBOC, then mBOC = 86° and arc BC has a measure of 86° as well. Angle BDC intercepts the arc BC which means half of the angle of arc BC is mBDC. So, mBDC = 43<span>°.</span>
kirill115 [55]3 years ago
6 0

It is B 43. This is correct for sure.

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Answer:

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Step-by-step explanation:

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The pyramid shown has a square base that is 32 32 centimeters on each side. The slant height is 24 24 centimeters. What is the l
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alex41 [277]

Answer: 14.48000 . . . ≤ t < 15.0000

Step-by-step explanation:

"Truncated by a hundreths of a second" means that the time was rounded to the nearest 0.0X second.  That would mean the reported time of 14.48 seconds was shortened from a time period having more digits to the right.  For example, If the time were actually 14.48223 seconds, the time was truncated to just 14.48 seconds.  The term used here. truncated, means that the digits after the hunredth place are simply dropped.  It doesn't say rounded, just truncated.  Brutal.  So that would mean that times between 14.48000 . . . and 14.48999 . . . would all be reported as 14.48 seconds.

So the time could actually be 14.48000 . . . ≤ t < 15.0000

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