Answer:
The 80,000
Step-by-step explanation:
 
        
                    
             
        
        
        
Answer:
The proof is below
Step-by-step explanation:
Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of a parallelogram bisect each other.
In ΔACD and ΔBEC
AD=BC              (∵Opposite sides of a parallelogram are equal)
∠DAC=∠BCE       (∵Alternate angles)
∠ADC=∠CBE        (∵Alternate angles)
By ASA rule, ΔACD≅ΔBEC
By CPCT(Corresponding Parts of Congruent triangles)
AE=EC and DE=EB
Hence, AE is conruent to CE and BE is congruent to DE