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2 years ago

14

Draw a line representing the "run" and a line representing the "rise" of the line. State the slope of the line in simplest form.

1 answer:

Igoryamba2 years ago

7 0

Answer:

The answer is " $\bold{\frac{9}{13}}$ "

Step-by-step explanation:

In this question, the image file is missing, which is defined in the attached file. please find it.

$\to raise= y_2-y_1$

$=-1-(-10)\\\\=-1+10\\\\=9$

$\to run= x_2-x_1$

$=9-(-4)\\\\=9+4\\\\=13$

$\to \text{formula for slope} =\frac{rise}{run} =\frac{9}{13}$

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Suppose that profit for a particular product is calculated using the linear equation: Profit = 20S + 3D. Which of the following

uranmaximum [27]

Answer:

b. S = 405, D = 0

Step-by-step explanation:

We have been given that profit for a particular product is calculated using the linear equation: $\text{Profit}=20S+3D$ . We are asked to choose the combinations of S and D that would yield a maximum profit.

To solve our given problem, we will substitute given values of S and D in the profit function one by one.

a. S = 0, D = 0

$\text{Profit}=20S+3D$

$\text{Profit}=20(0)+3(0)$

$\text{Profit}=0$

b. S = 405, D = 0

$\text{Profit}=20S+3D$

$\text{Profit}=20(405)+3(0)$

$\text{Profit}=8100+0$

$\text{Profit}=8100$

c. S = 0, D = 299

$\text{Profit}=20S+3D$

$\text{Profit}=20(0)+3(299)$

$\text{Profit}=0+897$

$\text{Profit}=897$

d. S = 182, D = 145

$\text{Profit}=20S+3D$

$\text{Profit}=20(182)+3(145)$

$\text{Profit}=3640+435$

$\text{Profit}=4075$

Since the combination S = 405, D = 0 gives the maximum profit ($8100), therefore, option 'b' is the correct choice.

7 0

3 years ago

The elevation of lake sam rayburn is 164 above mean sea level during the summer if it does not rain the elevation of the lake de

andrew-mc [135]

Answer:

I guess that you want to model the elevation of Lake Sam Rayburn.

During the summer, it is 165 ft above the sea level (the sea level is our position 0ft).

If it does not rain, the elevation of the lake decreases by 0.5ft each week.

So if we assume that there is no rain, we can write the elevation fo the lake as a linear relationship with slope equal to -0.5ft and y-intercept equal to 165ft.

L(w) = 165ft - 0.5ft*w

Where w is the number of weeks without rain, if we have 0 weeks without rain, then the level of the lake remains constant at 165ft above sea level,

L(0) = 165ft - 0.

4 0

3 years ago

A car rental company charges a one-time application fee of 40 dollars, 55 dollars per day, and 13 cents per mile for its cars. A

liberstina [14]

Answer:

A) C(d,m) = 40 + 55d + 0.13m

B) $448

Step-by-step explanation:

Let 'd' be the number of days and 'm' the number of miles driven.

A) The cost function that describes a fixed amount of $40, added to a variable amount of $55 per day (55d) and a variable amount of 13 cents per mile (0.13m) is:

$C(d,m) = 40 +55d +0.13m$

B) If d = 5 and m =600, the total cost is:

$C(5,600) = 40 +55*6 +0.13*600\\C(5,600)=\$448$

The cost is $448.

3 0

3 years ago

Read 2 more answers

How do you do this? This will be helpful with steps so i can understand this!

beks73 [17]

That looks very hard, keep trying with the steps so yeah

7 0

2 years ago

Which equation represents the function shown on the graph?

Anna11 [10]

Answer:

x = 0, y = 0

Step-by-step explanation:

4 0

2 years ago