Answer:
IDK i am trying to solve the same problem. I am sorry
Step-by-step explanation:
The quantity of water left in the tank as described in the task content is; 111 l 220ml.
<h3>What is the amount of water left in the tank?</h3>
The tank described in the task content initially contains 200 liters, in which case, 1 liter corresponds to 1000ml.
Hence, when 88l 580ml was used, the remaining quantity of water is; 200l - (88l 580ml) = 111 l 420ml.
And finally, since 200 ml leaked, the quantity of water left is; 111l 220ml.
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Well first you have to divide 3 by 4, which is 0.75 or 3/4
Distribute first
a(b+c)=ab+ac
7y(8y-7)=56y^2-49y
now we have
56y^2-49y+46y
56y^2-3y
tada
