Answer:
Here we have:
g(x) = 2*√x
And we know that it is related to a parent function, where the parent functions are:
Linear Function: f(x)=x.
Quadratic Function: ݂f(x)=x^2.
Square Root function: f(x)= √x.
Absolute Value function: f(x)=|x|
Cubic function: f(x)=x^3.
Cube Root function: f(x) = ∛x
Logarithmic function: f(x)=log x or f(x)=In x.
Exponential function: f(x) = a^x.
a) Because g(x) = 2*√x
We can see that it is related to the square root function, then the parent function is:
f(x) = √x
b) now we want to write g(x) in terms of f(x)
we have:
g(x) = 2*√x
we can replace √x by f(x)
then we get:
g(x) = 2*f(x)
Now we have g(x) in terms of f(x)
It can be -2,-6,-8 but not 10
Answer:
y=7-(8/5)x
Step-by-step explanation:
To solve for y we need to get Y on one side of the equation all by itself. To start we can move the 8x to the side with the 35 by subtracting 8x on both sides which gets us to 5y=35-8x then we just need to get the 5 detached from the y and we will have solved for Y. To do this we can divide by 5 on both sides to cancel out the 5 with the Y which leaves us with y=7-(8/5)x
I hope this helps and please don't hesitate to ask if there is anything still unclear!
The answer would be 5 and the work is down below
Integrating with shells is the easier method.
<em>V</em> = 2<em>π</em> ∫₁³ <em>x</em> (√<em>x</em> + 3<em>x</em>) d<em>x</em>
That is, at various values of <em>x</em> in the interval [1, 3], we take <em>n</em> shells of radius <em>x</em>, height <em>y</em> = √<em>x</em> + 3<em>x</em>, and thickness ∆<em>x</em> so that each shell contributes a volume of 2<em>π</em> <em>x</em> (√<em>x</em> + 3<em>x</em>) ∆<em>x</em>. We then let <em>n</em> → ∞ so that ∆<em>x</em> → d<em>x</em> and sum all of the volumes by integrating.
To compute the integral, just expand the integrand:
<em>V</em> = 2<em>π</em> ∫₁³ (<em>x </em>³ʹ² + 3<em>x</em> ²) d<em>x</em>
<em>V</em> = 2<em>π</em> (2/5 <em>x </em>⁵ʹ² + <em>x</em> ³) |₁³
<em>V</em> = 2<em>π</em> ((2/5 ×<em> </em>3⁵ʹ² + 3³) - (2/5 × 1⁵ʹ² + 1³))
<em>V</em> = 4<em>π</em>/5 (9√3 + 64)