Answer:
Only points on the circle satisfy the given inequality.
Step-by-step explanation:
Given: Unit circle
To find: portion of the unit circle which satisfies the trigonometric inequality 
Solution:
In the given figure, OA = 1 unit (as radius of the unit circle equal to 1)
= side opposite to
/hypotenuse
= side adjacent to
/hypotenuse


So, coordinates of A = 
For any point (x,y) on the unit circle with centre at origin, equation of circle is given by 
Put 

So,
satisfies the equation 
For points
inside the circle, 
For points
outside the circle, 
So, only points on the circle satisfy the given inequality.
Answer:((√2) + 2)/2
Step-by-step explanation:
(1+√2)/(√2) x ((√2)/(√2))
(√2(1+√2))/2
((√2)+2)/2
<span>You can calculate the following probabilities:
1. Given that a sampled student is in the Spanish Club, what is the probability they got the Spanish class they requested?
2. Given that a sampled student is not in the Spanish Club, what is the probability they got the Spanish class they requested? If there is a significant difference between the two probabilities, it indicates there is a bias in the selection procedure.
</span><span>Given that, a sampled student is in the Spanish Club, the probability they got the Spanish class they requested is given by 265/335. Given that, a sampled student is not in the Spanish Club, the probability they got the Spanish class they requested is given by 100/165.
</span>
<span>If a student is at the Spanish club, the probability they got the Spanish class they requested is 265/335 = 0.79. If a student is not in the Spanish club, the probability they got the Spanish class they requested is 100/165 = 0.61.
</span>
<span>Based on the calculation, all students do not have an equal chance of getting into the Spanish class that they requested.</span>
B. 712.50
40hrs x $15/hr= $600
5hrs OT x time & a half pay ($22.50)= $112.50
$600 + $112.50= $712.50
Answer:
Function B has a greater rate of change.
Function B has a greater y-intercept.
Step-by-step explanation:
Rate of change: rise ÷ run
Function A: (9-5)÷(3-1) = 2
Function B: 3 (based on equation)
Function A: 5-2 = 3
Function B: 4 (based on equation)