Question

What is the equation of a line in slope intercept form that passes through points (4,3) and (1,-6)

Answer 1

Answer:

y = 3x-9

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Step-by-step explanation:

To find the equation of a line that passes through two points, use point-slope form.

$y-y_{1} = m(x-x_{1})$ ...

where $(x_{1}, y_{1})$ is the first point, and $m$ is the slope.

Start with the slope (m). To find the slope, you find the change in y over change in x, or  $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$.

$\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ = $\frac{-6-3}{1-4}$ = $\frac{-9}{-3}$ = 3

$m=3$

Then, put the values into point-slope equation.

$y-y_{1} = m(x-x_{1})$  =  $y-3 = 3(x-4)$  =  $y-3 = 3x-12$  =  $y = 3x-9$