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3 years ago

What is the volume of the right rectangular prism, in cubic centimeters?

Mathematics

1 answer:

mylen [45]3 years ago

8 0

Answer:

108 cm³

Step-by-step explanation:

Formula: V = w×h×l

Solution: V = whl = 4·3·9 = 108

Hence, the answer is 108 cm³

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Vikentia [17]

Answer:

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3 years ago

Find the value of the variable y, where the sum of the fraction 2/y-3 and 6/y+3 is equal to the quotient.

NISA [10]

Answer:

Here we need to solve:

$\frac{2}{y - 3} + \frac{6}{y + 3 } = \frac{\frac{2}{y-3}}{\frac{6}{y + 3} }$

The sum of the fractions is equal to the quotient between the fractions.

Notice that the two values:

y = 3

y = -3

make the denominator equal to zero, so those values are restricted.

We can simplify the right side to get:

$\frac{2}{y - 3} + \frac{6}{y + 3 } = \frac{\frac{2}{y-3}}{\frac{6}{y + 3} } = \frac{2*(y + 3)}{6*(y - 3)} = 3*\frac{y + 3}{y - 3}$

Now we can multiply both sides by (y - 3)

$(y - 3)*(\frac{2}{y - 3} + \frac{6}{y + 3 }) = 3*(y + 3)\\2 + 6*\frac{y -3}{y + 3} = 3*(y + 3)$

Now we can multiply both sides by (y + 3)

$(2 + 6*\frac{y -3}{y + 3})*(y + 3) = 3*(y + 3)*(y + 3)$

$2*(y + 3) + 6*(y - 3) = 3*(y + 3)*(y + 3)\\\\2*y + 6 + 6*y - 18 = 3*(y^2 + 2*y*3 + 9)\\\\8*y - 12 = 3*y^2 + 6*y + 33\\\\0 = 3*y^2 + 6*y + 33 - 8*y + 12\\\\0 = 3*y^2 - 2*y + 45$

First, let's see the determinant of that quadratic equation:

$D = (-2)^2 - 4*3*45 = -536$

We can see that it is negative, thus, there are no real solutions of the equation.

Thus, there is no value of y such that the origina equation is true,

6 0

3 years ago

Given that CA = CB and m∠CPB = 90 degrees, which statement can you conclude is true?

UNO [17]

Answer:

3is the right answer

Step-by-step explanation:

you did it right

8 0

3 years ago

According to the box plot , what is the range and IQR of the data shown ?

vekshin1

Answer:

IQR= 14

Range=18

Hope this helps

6 0

4 years ago

=gx

inessss [21]

This is very confusing!!!!!!!!!1

7 0

3 years ago