Since 16 and 25 are perfect squares you can factor the first part.
4^2-5^2(b+3)^2
=(4-5(b+3))(4+5(b+3))
=(4-5b-15)(4+5b+15)
=(-11-5b)(19+5b)
Which can be expanded if necessary,
= -209+150b-25b^2
In order to find b1 from your formula stated we need to do few calculations
A=hb1+hb2, as you wee I multiply h with both bases( b1 and b2)
I will subtract hb2 from both sides
hb1=A-hb2
now I will divide my new expression by h
b1=(A-hb2)/h
Answer:
189282
Step-by-step explanation:
1. m angle 2 = 122
m angle 2 is congruent to m angle 4
2. m angle 1 = 58
m angle 1 is supplementary to m angle 2, so their sum is 180. Thus, m angle 1 + 122 = 180, so m angle 1 = 180 -122 = 58.
If you appreciated my explanation, a brainliest award would be most appreciated.
