The sum of the lengths of any two sides of a triangle must be greater than the length of the third side. Since 3in, 4in, and 8in. Since 6+14 > 10,6+ 10 > 14, and 10 + 14 > 6, you can form a triangle with the lengths 6m, 14m, and 10m.
For the GCF the answer is 7
In centre is the centre of a circle that is inscribed in a triangle, called the incircle, i.e. circle is tangent to all three sides AND located inside the triangle. An incircle is roughly sketched in the accompanying diagram.
Since all radii of an incircle are equal, we have
4x-1=6x-5
Solving for x,
6x-4x=5-1
x=2
consequently, distance from incentre to each side of the triangle is
4(2)-1=7
check 6x-5=6(2)-5=7... checks.
Answers:
The value of x = 2
The distance from incentre to side of triangle is 7
