Find the Reference Angle (4pi)/7 4π 7 4 π 7 Since the angle 4π 7 4 π 7 is in the second quadrant, subtract 4π 7 4 π 7 from π π.
Thus,
is your answer
Answer:
266.666667
Step-by-step explanation:
Answer:
Use the distance formula on both points AC and AB.
<em>Distance formula is this</em><em>:</em>
<em>\begin{gathered}d=\sqrt{(x2-x1)^2+(y2-y1)^2} \\\\d=\sqrt{(1--5)^2+(8--7)^2} \\\\d=\sqrt{(6)^2+(15)^2} \\\\d=\sqrt{36+225} \\\\d=\sqrt{261} \\\\\end{gathered}d=(x2−x1)2+(y2−y1)2d=(1−−5)2+(8−−7)2d=(6)2+(15)2d=36+225d=261</em>
Distance for AC is 16.16
Now do the same with the numbers for AB and get the distance of 5.39
2. To get the area, use the formula 1/2 x base x height
AB is the base and AC is the height.
1/2 x 16.16 x 5.39 = 43.55
the answer is 43.5
<u>Given</u>:
Given that the triangles ABD and CAD are similar.
The length of AB is 12.
The length of BD is x.
The length of AC is 27.
We need to determine the value of x.
<u>Value of x:</u>
Let us use the leg rule to determine the value of x.
Thus, we have;

Substituting the values, we get;

Cross multiplying, we get;


Dividing both sides by 27, we have;

Thus, the value of x is 
Hence, Option D is the correct answer.
Answer:
We know that the kite with the tail is 15 feet and 6 inches. While 6 inches is 0,50 foot, it's 15,5 feet. If the lenght of the kite is x, then:
15,5 = x + 1,5 + 2x
15,5 = 3x + 1,5 / - 1,5 (both sides)
14 = 3x / : 3 (both sides)
x ≈ 4,66
The kite is approx .4,66 feet long. It means that the tail is about 15,5 - 4,66 = 10,84 feet long.