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Yuri [45]
3 years ago
10

Compute the partial products.add them 349x 59

Mathematics
1 answer:
Semmy [17]3 years ago
8 0
20,591................
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57 1/2 as a decimal, Please help and Thanks
Nimfa-mama [501]
The answer is 57.5 because 57 represents a whole number and 1/2 equals .5 so 57.5.

People who answer the question will get a thank you!

4 0
3 years ago
Which system of inequalities is represented by the graph?
melisa1 [442]

Answer:

Option 3 is the correct answer.

Step-by-step explanation:

In this graph the red area is above the line y = -1 which represents y ≥ (-1)

Another graph is of a line y = mx + c which passes through (2, -1) and (0, 0)

where m = (y-y')/(x-x') = (1+0)/(0-2) = -1/2

and y intercept c = 0

Therefore line is y = -1/2x

and the blue area will be y ≤ -1/2x below the line.

Hence Option 3 is the answer.

3 0
3 years ago
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Can someone help me with these problems step by step? It’s pre-algebra so it’s not rlly that hard.
gtnhenbr [62]

Answer:

11

Step-by-step explanation:

√121=11 so right answer is B

5 0
3 years ago
Systems of equations and inequalities<br> solving systems by elimination<br> {y= -x+1<br> {y= 4x-14
kodGreya [7K]

Answer:

x = 3  , y = -2

Step-by-step explanation:

Solve the following system:

{y = 1 - x | (equation 1)

y = 4 x - 14 | (equation 2)

Express the system in standard form:

{x + y = 1 | (equation 1)

-(4 x) + y = -14 | (equation 2)

Swap equation 1 with equation 2:

{-(4 x) + y = -14 | (equation 1)

x + y = 1 | (equation 2)

Add 1/4 × (equation 1) to equation 2:

{-(4 x) + y = -14 | (equation 1)

0 x+(5 y)/4 = (-5)/2 | (equation 2)

Multiply equation 2 by 4/5:

{-(4 x) + y = -14 | (equation 1)

0 x+y = -2 | (equation 2)

Subtract equation 2 from equation 1:

{-(4 x)+0 y = -12 | (equation 1)

0 x+y = -2 | (equation 2)

Divide equation 1 by -4:

{x+0 y = 3 | (equation 1)

0 x+y = -2 | (equation 2)

Collect results:

Answer: {x = 3  , y = -2

5 0
3 years ago
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O<br>1.<br>Find the length of the segment AB shown below, if possible.<br>​
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Thus should be fun I know I might do
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