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Margaret [11]
3 years ago
12

Please help ill mark brainliest please

Chemistry
2 answers:
UkoKoshka [18]3 years ago
7 0

Answer:

The moons orbit around planets.

Mass is the force that holds people ans objects to earths surface.

Explanation:

frozen [14]3 years ago
5 0

Answer:

A, C, E, G

Explanation:

I think they are your answer

Can I have brainliest

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How many grams of iodine needs to be added to 950 ml of carbon tetrachloride to make a 0.75 m solution?
Black_prince [1.1K]
The unit "m" in this given is used to refer to molality which is equal to the number of moles of the solute divided by the mass in kg of the solvent. If we let x be the mass of iodine, the equation for molality then becomes,

    molality = (x / 253.8) / ((950 mL)(1.594 g/mL)(1 kg/ 1000 kg)

    0.75 = (x / 253.8) / 1.5143

The value of x 288.247 g

Answer: 288.25 g
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Write two equations for the neutralization of nitric acid, HNO, with magnesium hydroxide, Mg(OH). In the first equation, include
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where the formula

Explanation:

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Which characteristics belong to all members of the domain Eukarya? Check all that apply. have a cell wall are unicellular are mu
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Are multicellular is what i think
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why is chromatography not able to separate components of a solution which have same speed?Give reason.​
damaskus [11]

Answer:

The dyes which cover more surface area will travel more slowly. Similarly if two substances which have same speeds, they are going to travel together and they won't separate as chromatography separates substances having different rates or speeds for travelling

4 0
3 years ago
A sample of methane gas having a volume of 2.80 L at 25 degree C and 1.65 atm was mixed with a sample of oxygen gas having a vol
Svetradugi [14.3K]

Answer:

Volume of carbon dioxide = 2.47 L

Explanation:

Given that:

<u>For methane gas:-</u>

Temperature = 25.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (25.0 + 273.15) K = 298.15 K

V = 2.80 L

Pressure = 1.65 atm

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L atm/ K mol  

Applying the equation as:

1.65 atm × 2.80 L = n ×0.0821 L atm/ K mol  × 298.15 K  

<u>⇒n for methane gas = 0.1887 mol</u>

For oxygen gas:-

Temperature = 31 °C

T = (31 + 273.15) K = 304.15 K

V = 35.0 L

Pressure = 1.25 atm

Using ideal gas equation as:

PV=nRT

Applying the equation as:

1.25 atm × 35.0 L = n ×0.0821 L atm/ K mol  × 304.15 K  

<u>⇒n for oxygen gas = 1.7521 mol</u>

According to the reaction:-

CH_4+2O_2\rightarrow CO_2+2H_2O

1 mole of methane gas reacts with 2 moles of oxygen gas

Also,

0.1887 mole of methane gas reacts with 2*0.1887 moles of oxygen gas

Moles of oxygen gas = 0.3774 moles

Available moles of oxygen gas  = 1.7521 moles

Limiting reagent is the one which is present in small amount. Thus, methane gas is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

1 mole of methane gas on reaction forms 1 mole of carbon dioxide

Thus,

0.1887 mole of methane gas on reaction forms 0.1887 mole of carbon dioxide

Moles of carbon dioxide = 0.1887 moles

Given that:- Pressure = 2.50 atm

Temperature = 125 °C

T = (125 + 273.15) K = 398.15 K

Using ideal gas equation as:

PV=nRT

Applying the equation as:

2.50 atm × V = 0.1887 moles ×0.0821 L atm/ K mol  × 398.15 K  

<u>Volume of carbon dioxide = 2.47 L</u>

7 0
3 years ago
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