Answer:
False
The ester functional group is not symbolized as R-C-R
Explanation:
The general formula of ester functional group is RCOOR′ where R represents a hydrogen atom or aryl group or an alkyl group while R' represents the alkyl group or an aryl group
Hence, the given statement is false
Answer:
0.96 g/cm3, and it will float!
Explanation:
I've explained how to do this before (remember me? lol), but ig I'll do it again..
By looking at the graph you can see that Object C has a mass of ~24 grams and a volume of ~25 cm3
Density = Mass/Volume -> 24 grams/25 cm3 = 0.96 g/cm3
Density of water is 1 g/cm3
Object C is less dense than water and therefore will float (just barely, though)
:)
<u>Gay lussas law:</u>
Gay-Lussac law states that the pressure for a given gas’ mass changes directly to an absolute gas temperature, provided that the volume held to be constant. The mathematical expressions of Gay-Lussac law also correspond to those of Charles Law:
This gas law is important because it shows that an increase in gas temperature increases the pressure proportionally (if the volume does not change). Similarly, as the temperature decreases, the pressure decreases proportionally.
Answer:
(a) m = 0.327 m.
(b) m = 4.57 m.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to solve this problem by firstly considering the fact that the molality is computed by dividing the moles of solute by the kilograms of solvent, in this case water; in such a way, we proceed as follows:
(a) We firstly calculate the moles of 36.2 grams of sucrose as its molar mass is 342.3 g/mol:
Next, the kilograms of water in this case are 0.323 kg so that the molality will be:
(b) In this case, we directly realize that the kilograms of water are now 1.889 kg so that the molality will be:
Clearly, the both of them in molal, m, units.
Regards!
To determine the number or amount of carbon dioxide produced from the equation, we have to note from the given chemical reaction that the ratios of the moles of the participating reactants and the resulting products will be obtained.
The first step to answering this item is to determine the number of moles of CH4 by dividing the given amount in grams by the molar mass. Molar mass of methane, CH4, is equal to 16 g/mol.
The first conversion factor is therefore is 16 g/mol.