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3 years ago

. Find the common factor of terms 5a4+15a3 -10a2

Mathematics

1 answer:

Dafna1 [17]3 years ago

6 0

The common factor would be 5a2

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Limx→1 x 4 + 2x 2 − 3 x 2 − 3x + 2

spin [16.1K]

Answer:

2x −3x

Step-by-step explanation:

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3 years ago

A chef uses 3\frac{3}{4} pounds of semolina flour and 1\frac{5}{8} pounds of whole wheat flour for each batch of pasta she makes

Irina-Kira [14]

Answer:

huh ?

Step-by-step explanation:

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3 years ago

T-shirts are on sale for $4 off he regular price. Jeb buys 5 T-shirts for a total of 45.05, including a 6% sales tax. Which equa

Ksenya-84 [330]

Answer:

1.06 × 5(r-4) = 45.05

Step-by-step explanation:

Let r represents the regular price of each T-shirt,

After getting $ 4 off in regular price,

New price of each T-shirt = r - 4,

Thus, new price of 5 T-shirts = 5 × price of each T-shirt

= 5(r - 4)

Since, there is 6% sales tax,

Then, the final price after discount = 5(r - 4) + 6% of (5(r-4))

= 5(r-4) + 0.06(5(r-4))

= 1.06 × 5(r-4)

According to the question,

1.06 × 5(r-4) = 45.05

Which is the required equation.

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3 years ago

A net and four figures are shown: A net is shown on top. The net consists of 6 identical squares. There are 2 squares in a row,

Julli [10]

The net diagram could be a cube because a cube has 6 identical sides.

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3 years ago

Cos4theta+cos2theta/ cos4theta-cos2theta= _____

vovangra [49]

$\bf \textit{Sum to Product Identities} \\\\ cos(\alpha)+cos(\beta)=2cos\left(\cfrac{\alpha+\beta}{2}\right)cos\left(\cfrac{\alpha-\beta}{2}\right) \\\\\\ cos(\alpha)-cos(\beta)=-2sin\left(\cfrac{\alpha+\beta}{2}\right)sin\left(\cfrac{\alpha-\beta}{2}\right) \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \cfrac{cos(4\theta )+cos(2\theta )}{cos(4\theta )-cos(2\theta )}\implies \cfrac{2cos\left( \frac{4\theta +2\theta }{2} \right)cos\left( \frac{4\theta -2\theta }{2} \right)}{-2sin\left( \frac{4\theta +2\theta }{2} \right)sin\left( \frac{4\theta -2\theta }{2} \right)} \implies \cfrac{cos\left( \frac{6\theta }{2} \right)cos\left( \frac{2\theta }{2} \right)}{-sin\left( \frac{6\theta }{2} \right)sin\left( \frac{2\theta }{2} \right)}$

$\bf \cfrac{cos(3\theta )cos(\theta )}{-sin(3\theta )sin(\theta )}\implies -\cfrac{cos(3\theta )}{sin(3\theta )}\cdot \cfrac{cos(\theta )}{sin(\theta )}\implies -cot(3\theta )cot(\theta )$

8 0

3 years ago