Can someone please help fr.

Babies born after a gestation period of 32-35 weeks have a mean weight of 2700 grams and a standard deviation of 700 grams, whil

Nutka1998 [239]

Answer:

The 33 week gestation period baby has the higher z-score, so he weighs more relative to other babies of the same gestation period.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Who weighs more relative to other babies of the same gestation period?

Whoever has the higer z-score

33 - week baby.

Babies born after a gestation period of 32-35 weeks have a mean weight of 2700 grams and a standard deviation of 700 grams. A 33-week gestation baby weighs 2950 grams.

We have to find z when $\mu = 2700, \sigma = 700, X = 2950$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{2950 - 2700}{700}$

$Z = 0.357$

40-week baby

Mean weight of 3000 grams and a standard deviation of 490 grams. 40-week gestation baby weighs 3150 grams.

We have to find Z when $\mu = 3000, \sigma = 490, X = 3150$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3150 - 300}{490}$

$Z = 0.306$

The 33 week gestation period baby has the higher z-score, so he weighs more relative to other babies of the same gestation period.

6 0

4 years ago

How many triangles can be constructed with angles measuring 25 25 130?

Hoochie [10]

The answer is A one triangle all those angles equal 180

5 0

4 years ago

Read 2 more answers

(05.06 LC)

brilliants [131]

If we are to make x small rugs, each of which takes 2 hours to dye, then the total time taken to dye the small rugs is 2x. Similarly for the y large rugs which each take 3 hours to dye, the total time for dyeing the large rugs is 3y. Therefore the total for all sizes of rugs is 2x + 3y. Finally, we have a maximum of 60 available hours for the dyeing, so the total time cannot exceed 60, and the final inequality is
2x + 3y < 60

8 0

3 years ago

Type the correct answer in the box. use numerals instead of words. a population of beetles increases by 5% every year. if at the

Allushta [10]

At the end of the third year the population of beetles will be 11,576beetles

<h3>Exponential equations</h3>

The standard form of an exponential function is given as:

y = ab^t

Given the following parameters

initial population 'a" = 10,000 beetles

Time = 3 years

rate b = 1.05

Substitute into the formula

y = 10,000(1.05)^3

y = 10,000(1.1576)
y = 11,576 beetles

Hence at the end of the third year the population of beetles will be 11,576beetles

Learn more on exponential function here: brainly.com/question/12940982

#SPJ4

4 0

2 years ago

Polygon CCC has an area of 404040 square units. Kennan drew a scaled version of Polygon CCC using a scale factor of \dfrac12 2 1

dsp73

The area of polygon D is given by:
Ad = k ^ 2 * Ac
Where,
k: scale factor
Ac: area of polygon C
Substituting the values we have:
Ad = (1/2) ^ 2 * (40)
Ad = (1/4) * (40)
Ad = 10 square units
Answer:
the area of Polygon D is:
Ad = 10 square units

7 0

4 years ago

Read 2 more answers

Can someone please help fr.​

Can someone please help fr.