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3 years ago

10

Find the solutions to x2 = 28.

1 answer:

mr Goodwill [35]3 years ago

7 0

Answer: $x = \pm2\sqrt{7}\\\\$

Work Shown:

$x^2 = 28\\\\x = \pm\sqrt{28}\\\\x = \pm\sqrt{4*7}\\\\x = \pm\sqrt{4}*\sqrt{7}\\\\x = \pm2\sqrt{7}\\\\$

This can be rewritten into $x = 2\sqrt{7} \ \text{ or } \ x = -2\sqrt{7}$

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3 years ago

In ΔOPQ, the measure of ∠Q=90°, the measure of ∠P=54°, and OP = 68 feet. Find the length of PQ to the nearest foot.

andrey2020 [161]

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$PQ=40\ ft$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

In the right triangle OPQ

$cos(P)=\frac{PQ}{OP}$ ----> by CAH (adjacent side divided by the hypotenuse)

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$cos(54^o)=\frac{PQ}{68}$

solve for PQ

$PQ=(68)cos(54^o)=40\ ft$

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3 years ago