Question

Find the solutions to x2 = 28.

Answer 1

Answer: $x = \pm2\sqrt{7}$

Work Shown:

$x^2 = 28\\\\x = \pm\sqrt{28}\\\\x = \pm\sqrt{4*7}\\\\x = \pm\sqrt{4}*\sqrt{7}\\\\x = \pm2\sqrt{7}$

This can be rewritten into $x = 2\sqrt{7} \ \text{ or } \ x = -2\sqrt{7}$