Answer:
y + 13 = 5(x + 2)
Step-by-step explanation:
The slope-intercept form of the equation of a line is
y = mx + b,
where m = slope, and b = y-intercept.
From the slope-intercept equation y = 5x - 3, we see that the slope of the line is 3.
The point-slope form of the equation of a line is:
y - y1 = m(x - x1)
where m = slope, and (x1, y1) is a point on the line.
We have point (-2, -13), so x1 = -2, and y1 = -13.
We also have slope 5, so m = 5.
Now we use the coordinates of the given point and the slope in the point-slope equation.
y - (-13) = 5(x - (-2))
We simplify to get
y + 13 = 5(x + 2)
The maximum value attained by the function will be 4
4 = 4cos(2x - π)
cos(2x - π) = 1
2x - π = 0
x = (nπ)/2
From x = 0 to x = 2π, n = 1, 2, etc
The equation will yield +4 for odd values of n and -4 for even values of n
It would be 3/10 because you have to create a common denominator. That would be 10. 3x2=6 and 5x2=10, so 3/5 would become 6/10, which is equivalent. If you kept the denominators the same and subtracted the numerators, you would get 3/10.
X= 1 x+5/2=1 which is x .10/2
