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natima [27]
2 years ago
15

Factorize:(2a - b)² - (a - 2b)²​

Mathematics
2 answers:
bagirrra123 [75]2 years ago
7 0

Answer:

3(a - b)(a + b)

Step-by-step explanation:

Factorize: (2a - b)² - (a - 2b)²​

  • Different of Perfect a Square rule: a²​ - b²​ = (a + b)(a - b)

(2a - b)² - (a - 2b)²​ = [(2a - b) + (a - 2b)] × [(2a - b) - (a - 2b)]

1. Distribute and Simplify:

Distribute the (+) sign on the first bracket and simplify: [(2a - b) + (a - 2b)] → 2a - b + a - 2b → (3a - 3b)

Distribute the (-) sign on the first bracket and simplify: [(2a - b) - (a - 2b)] → 2a - b – a + 2b → (a + b)

We now have:

(3a - 3b)(a + b)

2. Factor out the Greatest Common Factor (3) from 3a - 3b:

(3a - 3b) → 3(a - b)

3. Add "(a + b)" back into your factored expression:

3(a - b)(a + b)

Hope this helps!

faltersainse [42]2 years ago
4 0

Answer:

3[a + b][a - b]

Step-by-step explanation:

Let us recall a useful formula. This formula can factorize any subtraction between perfect squares. The formula is known as a² - b² = (a - b)(a + b).

Let's apply the formula in the given expression as we can see that two perfect squares are being subtracted from each other. Then, we get:

\implies (2a - b)^{2}  - (a - 2b)^{2}

\implies [(2a - b) - (a - 2b)][(2a - b) + (a - 2b)]

Since the expression(s) inside the parentheses ( ) cannot be simplified further, we can open the parentheses ( ). Then, we get:

\implies [(2a - b) - (a - 2b)][(2a - b) + (a - 2b)]

\implies [2a - b - a + 2b][2a - b + a - 2b]

Now, we can combine like terms and simplify:

\implies [2a - b - a + 2b][2a - b + a - 2b]

\implies [a + b][3a - 3b]

Three is common in 3a - 3b. Thus, we can factor 3 out of the expression:

\implies [a + b][3a - 3b]

\implies [a + b] \times [3a - 3b]

\implies [a + b] \times 3[a - b]

\implies \boxed{3[a + b][a - b]}

Therefore, 3[a + b][a - b] is the factorized expression of (2a - b)² - (a - 2b)²​.

Learn more about factoring expressions: brainly.com/question/1599970

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