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stira [4]
3 years ago
9

3. A florist sells large floral arrangements for $50 each. Small floral arrangements sell for $15 each. Jenna is buying 2 large

floral arrangements and x small floral arrangements. Let y represent the total cost Jenna must pay in dollars.
(a) Write an equation in slope-intercept form to model this description.
(b) What is Jenna’s total cost given she purchases 4 small floral arrangements? Show your work.
Mathematics
1 answer:
motikmotik3 years ago
7 0

Answer:

a y=(15)x+100  

b y =(15) (4) +100    y =160

Step-by-step explanation:

y = mx + b

large arrangment cost $50

$50 x 2 = 100

b=100

x = the number of small arrangments that jenna is buying .in this case 4 so

x= 4

m is the cost of one small arranment so

m=15

y represents the total cost jenna pust may in dollars so you would do

15 x 4 =60  50x2=100  100 +60 = 160

giving y = 160

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kondor19780726 [428]

Answer: y=-61/2

Step-by-step explanation: - 4(8 + y)/-4 = 90/-4

8+y-8=-45/2-8

-8(2)-45/2

-16-45

-61

y=-61/2

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consider the function and then use calculus to answer the questions that follow 1 1/x 5/x^2 1/x^3 (a) Find the interval(s) where
boyakko [2]

Answer:

a)X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)

b)Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0  )

Step-by-step explanation:

From the question we are told that

The Function

f(x)=1+\frac{1}{x}  +\frac{5}{x^2} +\frac{1}{x^3}

Generally the differentiation of function f(x) is mathematically solved as

f(x)=1+\frac{1}{x}  +\frac{5}{x^2} +\frac{1}{x^3}

f(x)=\frac{x^3+x^2+5x+1}{x^2}

Therefore

f'(x)=\frac{x^2+10x+3}{x^4}

Generally critical point is given as

f'(x)=0

\frac{x^2+10x+3}{x^4}=0

x=-5 \pm\sqrt{22}

Generally the maximum and minimum x value for critical point is mathematically solved as

f'(-5 \pm\sqrt{22})

Where

Maximum value of x

f'(-5 +\sqrt{22})

Minimum value of x

f'(-5 +\sqrt{22})

Therefore interval of increase is mathematically given by

f'(-5 -\sqrt{22}),f'(-5 +\sqrt{22})

f(x)

Therefore interval of decrease is mathematically given by

(-\infty,-5 -\sqrt{22}),f'(-5 +\sqrt{22},0),(0,\infty)

Generally the second differentiation of function f(x) is mathematically solved as

f''(x)=\frac{2(x^2+15x+6)}{x^5}

Generally the point of inflection is mathematically solved as

f''(x)=0

x^2+15x+6=0

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x=\frac{1}{2} (-15 \pm \sqrt{201}

f''(x)>0,\frac{1}{2}(-15-\sqrt{201})

a)Generally the concave upward interval X is mathematically given as

X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)

f''(x)

b)Generally the concave downward interval Y is mathematically given as

Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0  )

5 0
2 years ago
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gregori [183]

Answer:

Granted that uppercase letters are the angles measurements and lowercase letters are the side lengths. I also was unable to round as I don't know to what decimal you need to round to.

First to find the measure of angle B, we must subtract A and C from 180

180-21-105=54

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Next, we can use the law of sines in order to find the measures of a and b

As a reminder, The law of sines is

\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}

First, lets solve for b

\frac{b}{sin54}=\frac{5}{sin105} \\\\b=\frac{(5)sin54}{sin105}\\\\b=4.187780119

Next lets solve for a

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Answer:

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Step-by-step explanation:

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This is in fact a line with an undefined slope. The slope for a perpendicular intersection is the opposite reciprocal of the slope.

Eg. If you have the line y = 2x

The reciprocal is y = 1/2x, the opposite means negative

So the slope that would intersect this line perpendicularly is y = -1/2x.

There is an undefined slope in this, therefore, you cannot find the slope for a line perpendicular to x = -6.

If it were an option, I would choose "no slope"

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