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3 years ago

9

In the last hour, 7 planes have landed at the airport and 11 planes have taken off. Use addition to find the change in the total

number of airplanes in the last hour

1 answer:

KatRina [158]3 years ago

7 0

7+11= 18 planes in the last hour

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Can someone help me with this please.

UkoKoshka [18]

This equals: x^3 + 5x^2 - 4x - 20
making the degree 3, the LC 1, and the y-int 20
hope this helps

6 0

3 years ago

Point a pq and r are collinear on pr and pq: pr =2/3. P is located on the origin q is located at (x,y) and r is located at (-12,

dybincka [34]

The values of x and y are 8 and 0 respectively.

<em><u>Explanation</u></em>

As 'p' is located at (0,0) and 'r' is located at (-12,0) , that means both 'p' and 'r' are on the x-axis. So point 'q' will be also on the x-axis , and 'q' is located at (x,y)

So, the value of y will be 0. That means the co ordinate of point 'q' is (x, 0)

Now, using the Distance formula, length of 'pq' $= \sqrt{(x-0)^2 +(0-0)^2}= \sqrt{x^2}= x$

and length of 'pr' $= \sqrt{(-12-0)^2+(0-0)^2}= \sqrt{144}=12$

Given that, pq : pr =2/3

So....

$\frac{x}{12} =\frac{2}{3}\\ \\ 3x=24\\ \\ x= \frac{24}{3}=8$

Thus, the values of x and y are 8 and 0 respectively.

8 0

4 years ago

Triangle V U W is shown. The length of side W V is 6 centimeters, the length of side W U is 3 StartRoot 3 EndRoot centimeters, a

Nat2105 [25]

Answer:

The angle measures of Δ VUW are m∠V = 60°, m∠U = 90°, m∠W = 30° ⇒ last answer

Step-by-step explanation:

In any triangle if the sum of the squares of the shortest two sides is equal to the square of the longest side, then the triangle is a right triangle and the angle opposite to the longest side is the right angle

In Δ VUW

∵ WV = 6 cm

∵ WU = 3 $\sqrt{3}$ cm

∵ UV = 3 cm

- Use the rule above tho check if it is a right Δ or not

∴ The longest side is WV

∴ The shortest two sides are WU and UV

∵ (WV)² = (6)² = 36

∵ (WU)² + (UV)² = (3 $\sqrt{3}$ )² + (3)² = 27 + 9 = 36

∴ (WV)² = (WU)² + (UV)²

- That means ∠U which opposite to WV is a right angle

∴ Δ VUW is a right triangle at ∠U

∴ m∠U = 90°

Let us use the trigonometry ratios to find m∠W and m∠V

→ sin Ф = $\frac{opposite}{hypotenuse}$

∵ UV is the opposite side of ∠W

∵ WV is the hypotenuse

∵ sin(∠W) = $\frac{UV}{WV}$

∵ sin(∠W) = $\frac{3}{6}=\frac{1}{2}$

- Use $sin^{-1}$ to find ∠W

∴ ∠W = $sin^{-1}(\frac{1}{2})$

∴ m∠W = 30°

∵ WU is the opposite side of ∠V

∵ WV is the hypotenuse

∵ sin(∠V) = $\frac{WU}{WV}$

∵ sin(∠V) = $\frac{3\sqrt{3}}{6}=\frac{\sqrt{3}}{2}$

- Use $sin^{-1}$ to find ∠V

∴ ∠V = $sin^{-1}(\frac{\sqrt{3}}{2})$

∴ m∠V = 60°

The angle measures of Δ VUW are m∠V = 60°, m∠U = 90°, m∠W = 30°

6 0

3 years ago

Read 2 more answers

If the perimeter of a right triangle is 42 units and the length of the hypotenuse is 20 units, find the length of the other two

Mashutka [201]

So
a^2+b^2=c^2
c=hypotenuse
a^2+b^2=20^2=400

if the permiter is 42 then
p=hypotonuse+side+side
42=20+side+side
subtract 20 from both sides
22=side+side

a+b=22
subtract b from both sides
a=22-b
subsitute for a in equation below
a+2+b^2=c^2
(22-b)^2+b^2=400
b^2-44x+484+b^2=400
2b^2-44x+484=400
divide both sides by 2
b^2-22x+242=200
subtract 200 from both sides
b^2-22x+42=0
factor
(b+/-number)(b+/-number)
to find the numbers, find which 2 number multiply to 42 and add to get -22
the numbers must be neative since same signs multiplied=positive and negative+negative=negative
(b-number)(b-number)
facrors of 42=2,3,6,7,14,21
2,21
3,14
6,7
it's hard to find the number, but the numbers are -19.8882 and -2.11181
(b-19.8882)(b-2.11181)=0
if xy=0 then assume that x and y=0

b-19.8882=0
add 19.8882 to both sides
b=19.8882

b-2.11181=0
add 2.11181 to both sides
b=2.11181

the side legnths are 19.8882 units and 2.11181 units

4 0

3 years ago

Question 4 (1 point)

vampirchik [111]

Answer:

wait Q1 is what and youahveto round all of them right

3 0

4 years ago

Read 2 more answers