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victus00 [196]
3 years ago
13

Write an expression in the factored form that represents the area of the border?​

Mathematics
1 answer:
Citrus2011 [14]3 years ago
3 0

Answer:

Step-by-step explanation:

( 3x+2*4) (12+ 2*4)=

(3x +8)( 12+8)

20(3x+8)

You might be interested in
In a school, only 13 out of 15 student participate in a competition.what is the probability of the student who do not makes it t
Papessa [141]

Answer:

\frac{2}{15}

Step-by-step explanation:

Number of students participating in the competition = 13.

Total number of students in the school = 15.

Thus ,

the number of students who did not make to this competition =

Total number of students - number of students participated

= 15-13 = 2.

Now ,

probability of the student who do not makes it to the competition

= fraction of students who did not make to this competition from the total number of students .

=\frac{2}{15}.

4 0
3 years ago
Find the equation of the line that contains the point (4,-2) and is perpendicular to the line y=-2x+8.
snow_tiger [21]

Answer:

\frac{1}{2} x - 4

Step-by-step explanation:

Perpendicular lines will have slopes that are the multiplicative additive inverse of each other: a line with slope 3/4 is perpendicular to a line with slope -4/3, for example.  You need a line that is perpendicular to a line with slope -2 (reading that from the -2 in the -2x portion of the given equation, which is written in slope-intercept form), so your new line must have slope +1/2.

With the slope and a point, we can come up with an equation using this formula:

y - y-coordinate = slope (x - x-coordinate)

So we have y - (-2) = 1/2 (x - 4).

Simplify the equation:  y + 2 = 1/2 x - 2

Subtract 2 from both sides: y + 2 - 2 = 1/2 x - 2 - 2

Simplify: y = 1/2 x - 4.

4 0
2 years ago
The probabilty that a student owns a car is 0.65 the porbability that a student owns a compuer is 0.82 the probability that a st
DanielleElmas [232]

Question:  The probability that s student owns a car is 0.65, and the probability that a student owns a computer is 0.82.

a. If the probability that a student owns both is 0.55, what is the probability that a randomly selected student owns a car or computer?

b. What is the probability that a randomly selected student does not own a car or computer?

Answer:

(a) 0.92

(b) 0.08

Step-by-step explanation:

(a)

Applying

Pr(A or B) = Pr(A) + Pr(B) – Pr(A and B)................. Equation 1

Where A represent Car, B represent Computer.

From the question,

Pr(A) = 0.65, Pr(B) = 0.82, Pr(A and B) = 0.55

Substitute these values into equation 1

Pr(A or B) = 0.65+0.82-0.55

Pr(A or B) = 1.47-0.55

Pr(A or B) = 0.92.

Hence the probability that a student selected randomly owns a house or a car is 0.92

(b)

Applying

Pr(A or B) = 1 – Pr(not-A and not-B)

Pr(not-A and not-B) = 1-Pr(A or B) ..................... Equation 2

Given: Pr(A or B)  = 0.92

Substitute these value into equation 2

Pr(not-A and not-B) = 1-0.92

Pr(not-A and not-B) = 0.08

Hence the probability that a student selected randomly does not own a car or a computer is 0.08

8 0
3 years ago
I need help solving these please help...
Ber [7]
5) y = 2x + 7
6) y = \frac{5}{4}x - 5.5
5 0
3 years ago
Idk this plz help me
Alik [6]

Answer:

1. {12,0}

hope it helps.

5 0
3 years ago
Read 2 more answers
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