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Darya [45]
2 years ago
5

The diameter of an insect cell is 1.7 × 10–11 meter. Ariel wants to find the length of the radius of the cell. If she performs t

he calculations on her calculator, which shows what will be displayed?
Mathematics
1 answer:
Juli2301 [7.4K]2 years ago
6 0

Answer:

8.5E-12

Step-by-step explanation:

According to the Question,

Given That, The diameter of an insect cell is 1.7 × 10^-11 meters.

Ariel wants to find the length of the radius of the cell. Radius Is Half of the Diameter.

  • Thus, R = D/2   ⇒  (1.7*10^-11)/2 = 0.85× 10^-11
  • If she performs the calculations on her calculator is 8.5E-12.
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PLEASE HELP!!! Division
krok68 [10]
The answer is 36/49.

You take the second fraction and flip it (it will be 12/14) and you multiply straight across. You get 72/98. You simplify it by finding it's greatest common factor (in this case it is 2) so you divide it the numerator and the denominator by 2. You get 36/49.
6 0
3 years ago
Plz help ASAP the number that is cut off on 69 is 24
Minchanka [31]

Answer:

A=256\ units^2

Step-by-step explanation:

The given figure shows a triangular pyramid having 16 units as height. The base of pyramid is triangle.

The area of a triangular pyramid is given by :

A=\dfrac{1}{3}bH

Where

b is the area of base

A=\dfrac{1}{3}\times \dfrac{1}{2}\times B\times h\times H\\\\=\dfrac{1}{6}\times 12\times 8\times 16\\\\=256\ units^2

So, the required area is equal to 256\ units^2.

7 0
3 years ago
1. What is the measure in radians for the central angle of a circle whose radius is 6 cm and intercept arc length is 5.4 cm?
fgiga [73]
Hello!

1.
find circumferece
c=2pir
c=2*6*pi=12pi
intercept is 5.4

2pi radians=all

part/whole=part/whole
5.4/12pi=x/2pi
times both sides by 12pi
5.4=6x
divide both sides by 6
0.9=x
answer is 0.9 radians



2. 
assuming 9pi/5 radians

find circumference
c=2pir
c=2*26.9*pi
c=53.8pi

arc/circumference=(9pi/5)/2pi

x/(53.8pi)=(9pi/5)/(2pi)
x/(53.8pi)=18/5
times both sides by 53.8pi
x=608.46266 m
about x=608.46 m


Hope this Helps! Have A Wonderful Day! :) 
5 0
3 years ago
Drag each tile to the correct box. not all tiles will be used.Chris plans to mulch the border surrounding a rectangular garden i
amm1812

Length (L): 2w + 3

width (w): w

border (b): \frac{1}{4} w

Area (A) = (L + b) * (w + b)   <em>NOTE: This is assuming the width also has a border</em>

              = (2w + 3 + \frac{1}{4} w) * (w + \frac{1}{4} w)

              = (2\frac{1}{4} w + 3)(1\frac{1}{4} w)

              = (\frac{9}{4} w + 3)(\frac{5}{4} w)

              = \frac{45}{16} w^2 + \frac{15}{4}w


5 0
3 years ago
A trapezoid has 8.2 millimeters base and 5.2 millimeters base, as well as 10 millimeters height. What is the area?
Savatey [412]

Answer:

67 mm

Step-by-step explanation:

use area of a trap formula:

b1+b2 /2*h

b1=base

b2=base

h=height

in our case it was, 8.2+5.2/2*10

67

6 0
3 years ago
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