3/4 of 16/9 = 12/9
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It’s impossible because any number divided by 0 will always just be 0
I will assume that you meant:
(x+4)/(-3x^2+12x+36) factor the denominator...
(x+4)/(-3(x^2-4x-12))
To factor a quadratic of the form ax^2+bx+c you need to find two values, j and k, which satisfy two conditions...
jk=ac=-12 and j+k=b=-4 so j and k must be 2 and -6 and the factors are then:
(x+2)(x-6) so we are now left with:
(x+4)/(-3(x+2)(x-6))
The only restriction on this function is that division by zero is undefined, so x cannot equal -2 or 6
Answer:
- FIRSTLY GET THE AREA OF THE WHOLE CIRCLE BY USING FORMULA
- THEN AFTER THAT DIVIDE THE AREA BY 2
- AFTER THAT UR ANSWER WILL COME
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