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Viefleur [7K]
3 years ago
10

Pls help with find the value of x​

Mathematics
1 answer:
vazorg [7]3 years ago
5 0

Answer:

x : 5

Step-by-step explanation:

I hope this is right! Good luck!

You might be interested in
Some parts of California are particularly earthquake-prone. Suppose that in one metropolitan area, of all homeowners are insured
ANTONII [103]

Missing part of the question

Some parts of California are particularly earthquake-prone. Suppose that in one metropolitan area, 25% of all homeowners.....................

Answer:

P(X = x) = ^4C_x * 0.25^x * 0.75^{4-x}

Mean = 1

Pr = 0.2617

Step-by-step explanation:

Given

n = 4

p = 25\%

Solving (a): The probability distribution of x

We have:

n = 4

p = 25\% = 0.25

The probability of not having earthquake insurance (q) is:

q = 1 - p

q = 1 - 0.25 = 0.75

If x has insurance, then n - x do not.

The distribution follows a binomial pattern. So, the probability distribution is:

P(X = x) = ^nC_x * 0.25^x * 0.75^{n-x}

Substitute 4 for n

P(X = x) = ^4C_x * 0.25^x * 0.75^{4-x}

Solving (b): The most likely value of x i.e. The mean

We have:

n = 4 and

p = 25\% = 0.25

Mean = np

Mean = 4 * 0.25

Mean = 1

Solving (c): At least 2 of 4 selected have earthquake insurance.

This is calculated as

Pr = P(x = 2) + P(x = 3) + P(x = 4)

P(X = x) = ^4C_x * 0.25^x * 0.75^{4-x}

P(X=2) = ^4C_2 * 0.25^2 * 0.75^{4-2}

P(X=2) = 6 * 0.25^2 * 0.75^2 = 0.2109375

P(X=3) = ^4C_3 * 0.25^3 * 0.75^{4-3}

P(X=3) = 4 * 0.25^3 * 0.75 = 0.046875

P(X=4) = ^4C_4 * 0.25^4 * 0.75^{4-4}

P(X=4) = 1 * 0.25^4 * 1= 0.00390625

So:

Pr = P(x = 2) + P(x = 3) + P(x = 4)

Pr = 0.2109375 + 0.046875 + 0.00390625

Pr = 0.26171875

Pr = 0.2617 --- approximated

6 0
4 years ago
What is your estimate for the number of airline flights in a year?
Firdavs [7]
The answer is between 45,000,000-65,000,000
8 0
4 years ago
A presidential candidate plans to begin her campaign by visiting the capitals in 4 of 42 states. What is the probability that sh
marissa [1.9K]

Answer:

P (She selects the route of four specific capitals) = \frac{1}{2686320}=(3.7226)10^{-7}

D. No,it is not practical to list all of the different possible routes because the number of possible permutations is very large.

Step-by-step explanation:

Let's start assuming that each route is equally likely to be chosen.

Assuming this, we can calculate P(A) where the event A is ''She selects the route of four specific capitals'' doing the following :

P(A) = Favourable cases in which the route of four specific capitals is selected / Total number of ways in 4 of 42 states

The favourable cases in which the route of four specific capitals is selected is equal to 1 .

For the denominator we need the permutation number of 4 in 42.

The permutation number is defined as :

nPr=\frac{n!}{(n-r)!}

42P4=\frac{42!}{(42-4)!}=\frac{42!}{38!}=2686320

The probability of event A is : \frac{1}{2686320}=(3.7226)10^{-7}

Finally for the other question : The option D is the correct because the number of possible permutations is 2686320 and is very large to be listed.

7 0
3 years ago
Can you guys please help me with this? :)
xxMikexx [17]

Answer:

bob

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
I need help with this question?
madam [21]
I have the answer attached.

5 0
4 years ago
Read 2 more answers
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