Why are numbers with a five in the ones place not prime numbers
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
Let A = R−{0}, the set of all nonzero real numbers, and consider the following relations on A × A.
Given that (a,b) R (c,d) if
Or (a,b) R (c,d) if determinant
a) Reflexive:
We have (a,b) R (a,b) because ab-ab =0 Hence reflexive
b) Symmetric
(a,b) R (c,d) gives ad-bc =0
Or da-cb =0 or cb-da =0 Hence (c,d) R(a,b). Hence symmetric
I think you mean,
You can use the usual formula,
That in this case is,
Where I have used,
You can use the usual formula,
That in this case is,
Where I have used,