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WINSTONCH [101]
3 years ago
15

Graph the points (0, -2), (4, 0) and (2, 0). If you want to create a parallelogram, which of the following points should be used

for the fourth point?
1. (-1, 0)
2. (-4, 0)
3. (4, 4)
4. (2, -2)


NO LINKS
Mathematics
2 answers:
telo118 [61]3 years ago
8 0
You would want the fourth point to be (2, -2) so it can form a rhombus.
Wewaii [24]3 years ago
7 0
It is would be 4, (2, -2)
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<u>The question does not clearly specify from which endpoint Q is at 2/3. I'll assume Q is 2/3 away from R.</u>

Answer:

<em>The point Q is (2,3)</em>

Step-by-step explanation:

Take the aligned points R(-2,1), S(4,4), and Q(x,y) in such a way that Q is 2/3 away from R (assumed).

The required point Q must satisfy the relation:

d(RQ) = 2/3 d(RS)

Where d is the distance between two points.

The horizontal and vertical axes also satisfy the same relation:

x(RQ) = 2/3 x(RS)

x_R-x_Q=2/3(x_R-x_S)

And, similarly:

y_R-y_Q=2/3(y_R-y_S)

Working on the first condition:

-2-x=2/3(-2-4)=2/3(-6)

Removing the parentheses:

-2-x=-4

Adding 2:

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Similarly, working with the vertical component:

1-y=2/3(1-4)=2/3(-3)

Removing the parentheses:

1-y=-2

Subtracting 1:

-y = -3

y = 3

The point Q is (2,3)

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An iceberg has a volume of 7685 cubic feet. What is the mass of the ice (in kg) composing the iceberg?
Ksju [112]

Volume of an iceberg = 7685 cubic feet

Since, density of ice = 0.917 g/cm^3

We have to determine the mass of the ice.

Since density = mass \times volume

Since the unit of density is in g/cm^3, first we will convert the density unit in kilogram.

Since, 1 kilogram = 1000 gram

Therefore, density = \frac{0.917}{1000} kg/cm^3

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Since, the density unit is in cubic centimeter. We will convert it into cubic feet.

1 cubic centimeter = 0.00003531466 cubic feet

Therefore, 0.000917  kg/cm^3 = 0.000917 x 0.00003531466

= 0.0000000323 kg/ft^3.

Now, mass = density \times volume

= 0.0000000323 \times 7685

= 0.000248

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Therefore, the mass of ice is 0.00025 kg.

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4 years ago
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timofeeve [1]

Answer: B

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Solve the inequality W &gt; Y plus H all divided by P for H.
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