The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
_____
You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
Answer:
$31.50
Step-by-step explanation:
3j = $94.50
j = 94.50 / 3
j = $31.50
Between the 4 and the 7 is it a multiplication or an X?
If the multiplication sign, this is the solution
Answer:
x^2 + 2x +1 = 2x + 2
Step-by-step explanation:
(x+1) = 2
multiplying both sides by x +1
(x +1) (x+1) = 2 (x+1)
x^2 + 2x +1 = 2x + 2
Answer:
$2025
Step-by-step explanation:
Hope that helps!
