The factored form of the polynomial function is y(x) = (x + 3)²(x - 4)(x - 2)
<h3>How to determine the factored form?</h3>
The given parameters are:
- Leading coefficient, a = 1
- Zeros = -3, -3, 4, and 2.
Rewrite the zeros as:
x = -3, x = -3, x = 4 and x = 2
Set the zeros to 0
x + 3 = 0, x + 3 = 0, x - 4 = 0 and x - 2 = 0
Multiply the zeros
(x + 3) * (x + 3) * (x - 4) *(x - 2) = 0
Express as a function
y(x) = a(x + 3) * (x + 3) * (x - 4) *(x - 2)
Substitute 1 for a
y(x) = (x + 3)²(x - 4)(x - 2)
Hence, the factored form of the polynomial function is y(x) = (x + 3)²(x - 4)(x - 2)
Read more about polynomials at:
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Answer:
(A) 509.78
We need to move the decimal point after the first non-zero digit
So,
=> 5.0978 × 10² (Since the decimal point is moved two places to the left)
(B) 0.0289
Again after the first non-zero digit:
So, it becomes:
=> 2.89 × 10⁻² (Since the decimal point is moved 2 places to the right so it will be negative also)
<span>i Ace</span>hello :
let : A(-6,6) B(6,-2)
the center is w((-6+6)/2 , (6-2)/2)....(midel <span>[ AB]
w(0 ,2)
the ridus is : r = AB/2
AB = </span>√(-6-6)²+(6+2)² = √(144+64) =<span>√208/2
</span>an equation in <span>standard form equation of the circle :
</span>(x+0)²+(y-2)² = (√208/2)²=208/4 = 52
Is 19%i already pass that it was easy
