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WINSTONCH [101]
3 years ago
11

1. What are the opposite and absolute value of: a) 7.2 ____,____ b) -3.5 ____, ____ c) 5 ½ ____,____

Mathematics
2 answers:
NARA [144]3 years ago
7 0

Opposite value would be either changing from a positive to a negative or from a negative to a positive.

Absolute value is always a positive value

A) 7.2, -7.2, 7.2

B) -3.5, 3.5, 3.5

C) 5 1/2, -5 1/2, 5 1/2

Sloan [31]3 years ago
3 0

Answer:

-7.2     7.2

3.5      3.5

-5 1/2   5 1/2

Step-by-step explanation:

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Find the AREA of the triangle below. Round your answer to the nearest tenth.
nordsb [41]

Step-by-step explanation:

4+2+2+4+5 - 17

in nearest ten - 100 but i am not sure

7 0
3 years ago
Given that the area of rectangle IJKL 500 what are it’s length and width
Art [367]

Answer:

Length=5

Width=100

Step-by-step explanation:

area of a rectangle=length x width

500= 5 x 100

500=500

5 0
3 years ago
Ursula counted out the gummy bears and found 30 to be red. 4/15 were green and 1/3 were yellow . how many are green?
Brums [2.3K]

Answer:

I D K

Step-by-step explanation:

5 0
3 years ago
Allison measured a line to be 5.4 inches long. If the actual length of the line is 5.5 inches, then what was the percent error o
valentina_108 [34]

Answer:

1.85%

Step-by-step explanation:

→ Find the difference between the actual and predicted

5.5 - 5.4 = 0.1

→ Divide answer by 5.4

0.1 ÷ 5.4 = 0.01851851851

→ Multiply answer by 100

0.01851851851 × 100 = 1.85%

7 0
2 years ago
A lathe is set to cut bars of steel into lengths of 6 cm. The lathe is considered to be in perfect adjustment if the average len
Gnom [1K]

Answer:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

df=n-1=93-1=92  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

Step-by-step explanation:

Information provided

\bar X=5.97 represent the sample mean for the length

s=0.4 represent the sample standard deviation

n=93 sample size  

\mu_o =6 represent the value that we want to test

\alpha=0.05 represent the significance level

t would represent the statistic  

p_v represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:  

Null hypothesis:\mu = 6  

Alternative hypothesis:\mu \neq 6  

since we don't know the population deviation the statistic is:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing in formula (1) we got:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

P value

The degrees of freedom are given by:

df=n-1=93-1=92  

Since is a two tailed test the p value would be:  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

5 0
3 years ago
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