Do 35 times 19 and that is the whole square inches or so 35 squared times 19 squared
Part (a)
There are 7 red out of 7+3 = 10 total
<h3>Answer: 7/10</h3>
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Part (b)
We have 3 green out of 10 total
<h3>Answer: 3/10</h3>
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Part (c)
3/10 is the probability of getting green on any selection. This is because we put the first selection back (or it is replaced with an identical copy)
So (3/10)*(3/10) = 9/100 is the probability of getting two green in a row.
<h3>Answer: 9/100</h3>
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Part (d)
Similar to part (c) we have 7/10 as the probability of getting red on each independent selection.
(7/10)*(7/10) = 49/100
<h3>Answer: 49/100</h3>
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Part (e)
7/10 is the probability of getting red and 3/10 is the probability of getting green. Each selection is independent of any others.
(7/10)*(3/10) = 21/100
<h3>Answer: 21/100</h3>
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Part (f)
We have the exact same set up as part (e). Notice how (7/10)*(3/10) is the same as (3/10)*(7/10).
<h3>Answer: 21/100</h3>
Answer:
No. See explanation below.
Step-by-step explanation:
No.
Since 60 × $300 = $18,000, he would be exactly at budget if he needed 60 uniforms and if each uniform cost $300, but he needs more than 60 uniforms, and each uniform costs more than $315, so the total cost is definitely more than $18,000.
A) The membership cost starts at $23 and it adds $6 every year. The 23 would be your b and the 6 would be your slope, m, in the form y=mx+b.
y=6x+23
This equation means that you're starting at 23 dollars and adding 6 dollars with every x you add.
B) 2009-1995=14 This means that there's 14 years that the cost increased. 14*6=$84 The membership cost increased by anther $84 over the 14 years. You have to add 84 to 23 to find your total=$107.
C) Set $85 equal to 6x+23
85=6x+23
6x=62
x≈10
10 years later the cost will be $85.
1995+10=2005
Responder:
42 bombones
Explicación paso a paso:
Dado que :
Número de bombones = 60
Cantidad consumida por Eba = 1/5 * 60 = 12
Cantidad comida por Ana = 1/2 * 60 = 30
Cantidad de chocolate que comieron Eba y Ana:
(12 + 30) = 42
De ahí que Ana y Eba se comieran 42 bombones