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LekaFEV [45]
3 years ago
10

SOMEONE PLEASE HELP I WILL GIVE BRAIN LIEST 6TH GRADE MATH

Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
6 0

Answer:

29% of squares are shaded

61% of squares are not shaded

Step-by-step explanation:

Karolina [17]3 years ago
3 0

Answer: 29% shaded

71% unshaded

Step-by-step explanation:

100 squares in grid

count shaded squares

subtract shaded from total

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If (6y − 11)(6y 11) = ay^2 − b, what is the value of a? the value of a is ____________.
Triss [41]
(6y - 11)(6y + 11) = ay² - b    |use (a - b)(a + b) = a² - b²

(6y)² - 11² =ay² - b

36y² - 121 = ay² - b    |add b to both sides

ay² = 36y² - 121 + b        |divide both sides by y² ≠ 0

a = (36y² - 121 + b)/y²

\boxed{a=\dfrac{36y^2-121+b}{y^2}}
7 0
3 years ago
How do i draw a decimal for example 0.26?
elixir [45]
First, you need convert the decimals into fraction

0.26 = 26/100 = 13/50

The next step would be drawing 50 small boxes on a piece of paper. Make it colorless.

The final stap would be giving 13 out of those 50 boxes with different color (such as black), and you're done

8 0
4 years ago
Read 2 more answers
I really need help with this. You can answer this at any time if you want.​
Tcecarenko [31]

Answer:

1. a 3d rectangle

2. 40 in cubed

3. repeat

4. another repeat

Step-by-step explanation:

8 0
2 years ago
Question 1 (2 points)
vitfil [10]

Answer:

11

Step-by-step explanation:

121/11=11

5 0
3 years ago
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Car A, traveling at a constant 10 m/s, crosses the start line 3 seconds before Car B, who is traveling at a constant 15 m/s. At
Margaret [11]
The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
 
Distance traveled by car A =x,  (when the car B is at the same distance from the start line)
time of car A=t

x=10 m/st  ⇒    x=10t    (1)

Distance traveled by car B=x
time of car B=t-3

x=15(t-3)  (2)

With the equations (1) and (2) we make a system of equations:

x=10t
x=15(t-3)

We solve this system of equations:

10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9

t-3=9-3=6

x=10 t=10 (9)=90

Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
8 0
3 years ago
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