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Ulleksa [173]
3 years ago
5

Prove that the diagonals of a rectangle bisect each other.

Mathematics
1 answer:
Kobotan [32]3 years ago
8 0

Answer:

  bisect each other.

Step-by-step explanation:

The midpoints are the same point, so the diagonals bisect each other.

__

<em>More elaboration on a proof</em>

The alternate interior angles formed by diagonals and the sides of the triangle are congruent, so the (point-to-point) triangles formed by the crossing diagonals are congruent ASA. Since the sides of those triangles are congruent, the diagonals meet at their midpoints. That is, the diagonals bisect each other.

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when u are doing a rotation and it’s a 90 degrees. Do you have to flip the coordinates and change the signs?
Anuta_ua [19.1K]
Hello!

When doing a 90 degree reparation you flip the coordinates and apply to the sign of the quadrant.

For example, If it flips into quadrant one, they will both be positive.

So, in this case it would be Triangle 4.

Hope this helped!
5 0
3 years ago
A fast-food restaurant offers 6 different burgers, 6 different side orders, 7 different flavor drinks, and 9 different flavors o
dangina [55]

Answer:

Total no of ways can a combo containing 2 burgers, 3 different sides, 2 different flavor drinks, and 3 ice cream flavors be made = 529,200

Step-by-step explanation:

Given -

A fast-food restaurant offers 6 different burgers, 6 different side orders, 7 different flavor drinks, and 9 different flavors of ice cream .

choose 2 burgers from 6 different burger = \binom{6}{2}

choose 3 different sides from  6 different side orders = \binom{6}{3}

choose 2 flavor drinks from 7 different flavor drinks = \binom{7}{2}

choose 3 ice cream from   9 different flavors of ice cream = \binom{9}{3}

Total no of ways can a combo containing 2 burgers, 3 different sides, 2 different flavor drinks, and 3 ice cream flavors be made=

= \binom{6}{2}\times\binom{6}{3}\times\binom{7}{2}\times\binom{9}{3}          ( Using combination )

= \frac{6!}{(2!)(4!)}\times\frac{6!}{(3!)(3!)}\times\frac{7!}{(2!)(5!)}\times\frac{9!}{(3!)(6!)}

= 15\times20\times21\times84

= 529,200

4 0
3 years ago
A or D i'm having a little trouble with this
sergeinik [125]
I believe it’s D bc I went over A and it doesn’t add up
3 0
3 years ago
Estimate 7.411*47hhhhhhhhhhhhh
jenyasd209 [6]

7*50=350

350 is da answer so yeah

6 0
3 years ago
If the function f(x)=2x-3 and g(x)= 3/2x + 1 which is a tru statement?
Sunny_sXe [5.5K]

Answer: 3 f(8)=g(8)

Step-by-step explanation:

2(8)-3=3/2(8)+1

16-3=12+1

13=13

6 0
3 years ago
Read 2 more answers
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